分块——入门2

水题爆炸记

这里写图片描述

woc这题卡了我一天,这么水的题,我真的**无语,先是发现二分写错了,然后发现建立块都写错了,我真的无语了。
上代码(舞草):

//By Bibi
///                 .-~~~~~~~~~-._       _.-~~~~~~~~~-.
///             __.'              ~.   .~              `.__
///           .'//                  \./                  \\`.
///        .'//                     |                     \\`.
///       .'// .-~"""""""~~~~-._     |     _,-~~~~"""""""~-. \\`.
///     .'//.-"                 `-.  |  .-'                 "-.\\`.
///   .'//______.============-..   \ | /   ..-============.______\\`.
/// .'______________________________\|/______________________________`.
#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<=b;++i)
#define dep(i,a,b) for(int i=a;i>=b;--i)
#define pl sort(d+l[be[L]],d+r[be[L]]+1)
#define pr sort(d+l[be[R]],d+r[be[R]]+1)
using namespace std;
const int MAXN=5e4+5;
int read()
{
    int sum=0,flag=1;
    char c;
    for(;c<'0'||c>'9';c=getchar())if(c=='-') flag=-1;
    for(;c>='0'&&c<='9';c=getchar())sum=(sum<<1)+(sum<<3)+c-'0';
    return sum*flag;
} 
int n;
int a[MAXN],op,c;
int d[MAXN];
int num;
int block;
int be[MAXN],l[MAXN],r[MAXN],L,R;
int p[MAXN];
void build()
{
    block=sqrt(n);
    num=n/block;
    if(n%block) num++;
    rep(i,1,n) be[i]=(i-1)/block+1,d[i]=a[i];
    rep(i,1,num)
    {
        l[i]=(i-1)*block+1;
        r[i]=i*block;
    }
    r[num]=n;
    rep(i,1,num) sort(d+l[i],d+r[i]+1);
}
void ask()
{
    int ans=0;
    if(be[L]==be[R])
    {
        rep(i,L,R) if(a[i]+p[be[i]]<c) ans++;
        printf("%d\n",ans);
    }
    else
    {
        rep(i,L,r[be[L]]) if(a[i]+p[be[i]]<c) ans++;
        rep(i,l[be[R]],R) if(a[i]+p[be[i]]<c) ans++;
        rep(i,be[L]+1,be[R]-1)
        {
            int ll=l[i],rr=r[i],result=0,mid; 
            if(d[l[i]]+p[i]>=c) continue;
            while(ll+1<rr)
            {
                mid=(ll+rr)>>1;
                if(d[mid]+p[i]<c) ll=mid;
                else rr=mid;
            }
            if(d[rr]+p[i]<c) ans+=rr-l[i]+1;
            else ans+=ll-l[i]+1;
        }
        printf("%d\n",ans);
    }
}
void add()
{
    if(be[L]==be[R])
    {
        rep(i,L,R) a[i]+=c;
        rep(i,l[be[L]],r[be[L]]) d[i]=a[i];
        pl;
    }
    else
    {
        rep(i,L,r[be[L]]) a[i]+=c;
        rep(i,l[be[L]],r[be[L]]) d[i]=a[i];
        pl;
        rep(i,l[be[R]],R) a[i]+=c;
        rep(i,l[be[R]],r[be[R]]) d[i]=a[i];
        pr;
        rep(i,be[L]+1,be[R]-1) p[i]+=c;
    }
}
void init()
{
    n=read();
    rep(i,1,n) a[i]=read();
    build();
    rep(i,1,n)
    {
        op=read();
        if(op)
        {
            L=read(),R=read(),c=read(),c=c*c;
            ask();
        }
        else
        {
            L=read(),R=read(),c=read();
            add();
        }
    }
}
int main()
{
    init();
    return 0;
}

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转载自blog.csdn.net/bbbblzy/article/details/79531952
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