New Code Day15

1.一个数组中只有两个数字是出现一次, 其他所有数字都出现了两次。 找出这两个数字,编程实现。

#define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <assert.h>

void find_num(int *arr,int len)
{
	int flag;
	int i = 0,j = 0;
	assert(arr);
	for(i=0; i<len; i++)
	{
		flag = 1;
		for(j=0; j<len; j++)
		{
			if(i == j)
				j++;
			else if(arr[i] == arr[j])
				flag = 2;
		}
		if(1 == flag)
		{
			printf("%d ",arr[i]);
		}
	}
	
}

int main()
{
	int arr[] = {1,2,3,4,5,6,5,4,3,2,1,7};
	int len = sizeof(arr)/sizeof(arr[0]);
	find_num(arr,len);
	return 0;
}

2.喝汽水,1瓶汽水1元,2个空瓶可以换一瓶汽水, 给20元,可以多少汽水。 编程实现。

#define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <assert.h>


//2.0递归版
int In_soda(int num)
{ 
	if(2 >= num)
		return 1;
	else
		return num/2 + In_soda((num/2+num%2));
}
int main()
{
	printf("%d\n",20+In_soda(20));
	return 0;
}

//1.0普通版
int In_soda(int num)
{
	int ret = num; 
	while(num>1)
	{
		ret += num/2;
		num = num/2 + num%2;
	}
	return ret;
}

int main()
{
	printf("%d\n",In_soda(20));
	return 0;
}

3.模拟实现strcpy

define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <assert.h>

void my_strcpy(char *dst,const char *src)
{
	assert(dst);
	assert(src);
	while(*dst++ == *src++ && *src != '\0')
	{
		;
	}
}
int main()
{
	char src[] = "def";
	char dst[] = "abc";
	my_strcpy(dst,src);
	printf("%s",dst);
	return 0;
}

4.模拟实现strcat

#define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <assert.h>

void my_strcat(char *dst,const char *src)
{
	char *tmp = dst;
	assert(dst);
	assert(src);
	while(*tmp != '\0'){tmp++;}
	while(*src != '\0')
	{
		*tmp++ = *src++ ;
	}
	*tmp = '\0';
}

int main()
{
	char src[] = "efg";
	char dst[20] = "abcd";
	my_strcat(dst,src);
	printf("%s\n",dst);
	return 0;
}

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转载自blog.csdn.net/quchen528/article/details/83691885