Codeforces 637A Voting for Photos 【水题】

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/weixin_39645344/article/details/83045773

http://codeforces.com/problemset/problem/637/A

A. Voting for Photos

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

After celebrating the midcourse the students of one of the faculties of the Berland State University decided to conduct a vote for the best photo. They published the photos in the social network and agreed on the rules to choose a winner: the photo which gets most likes wins. If multiple photoes get most likes, the winner is the photo that gets this number first.

Help guys determine the winner photo by the records of likes.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 1000) — the total likes to the published photoes.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 1 000 000), where ai is the identifier of the photo which got the i-th like.

Output

Print the identifier of the photo which won the elections.

Examples

input

Copy

5
1 3 2 2 1

output

Copy

2

input

Copy

9
100 200 300 200 100 300 300 100 200

output

Copy

300

找出现最多的数,有多个输出出现靠前的数。

#include <cstdio>
#include <queue>
#include <cstring>
#include <iostream>
#include <cstdlib>
#include <algorithm>
#include <vector>
#include <map>
#include <string>
#include <set>
#include <ctime>
#include <cmath>
#include <cctype>
using namespace std;
#define maxn 1000005
#define LL long long
int cas=1,T;
map<int,int>a;
int main()
{
	int n;
	while (scanf("%d",&n)!=EOF)
	{
		int ans = 0,maxx=0;
		for (int i = 0;i<n;i++)
		{
			int temp;
			scanf("%d",&temp);
			a[temp]++;
            if (a[temp]>maxx)
			{
				maxx=a[temp];
				ans=temp;
			}
		}
		printf("%d\n",ans);
	}
	//freopen("in","r",stdin);
	//scanf("%d",&T);
	//printf("time=%.3lf",(double)clock()/CLOCKS_PER_SEC);
	return 0;
}

猜你喜欢

转载自blog.csdn.net/weixin_39645344/article/details/83045773