[ARC062]F - Painting Graphs with AtCoDeer (tarjan求双联通分量+Pólya定理)

参考题解

#include"bits/stdc++.h"
using namespace std;
typedef long long LL;
const int MX = 1e3+7;
const int mod = 1e9+7;
int n,m,K;
LL fac[MX], inv[MX];
LL ans = 1;

void init()
{
    int n = 1e3;
    fac[0] = fac[1] = inv[0] = inv[1] = 1;
    for(int i = 2; i <= n; i++){
        fac[i] = fac[i-1]*i%mod;
        inv[i] = (mod-mod/i)*inv[mod%i]%mod;
    }
    for(int i = 2; i <= n; i++)
        inv[i] = inv[i]*inv[i-1]%mod;
}

LL qpow(LL a, LL n)
{
    LL ret = 1;
    while(n){
        if(n&1) ret = ret * a %mod;
        a = a*a%mod;
        n >>= 1;
    }
    return ret;
}

LL polya(int m)
{
    LL ret = 0;
    for(int i = 1; i <= m; i++){
        ret += qpow(K,__gcd(i,m));
        ret %= mod;
    }
    return (ret*qpow(m,mod-2))%mod;
}

LL C(int n, int m)
{
    if(n < m) return 0;
    return fac[n]*inv[m]%mod*inv[n-m]%mod;
}

struct edge{
    int v;
    bool vis;
    edge *nxt,*rev;
}*con[MX],*stc[MX];

int dfn[MX],low[MX],tim,top;
bool vis[MX];

void add(int u, int v)
{
    edge *p = new edge;
    p->v = v;   p->vis = 0;
    p->nxt = con[u];
    con[u] = p;
}
void get_rev(int u, int v)
{
    con[u]->rev = con[v];
    con[v]->rev = con[u];
}

void tarjan(int u)
{
    dfn[u] = low[u] = ++tim;
    for(edge *p = con[u]; p; p = p->nxt){
        if(p->vis || p->rev->vis) continue;
        stc[++top] = p;
        p->vis = p->rev->vis = 1;
        if(!dfn[p->v]){
            tarjan(p->v);
            low[u] = min(low[u], low[p->v]);
            if(low[p->v] >= dfn[u]) {
                bool cir = 1;   //用来判断一个环的点双联通分量与多重环的点双联通分量
                int cnt = 0;
                for(int i = top; stc[i+1] != p; --i,++cnt){
                    if(vis[stc[i]->v]) cir = 0;
                    else vis[stc[i]->v] = 1;
                }
                for(; stc[top+1] != p; --top) vis[stc[top]->v] = 0;

                if(cir) ans = (ans*polya(cnt))%mod;
                else ans = (ans*C(cnt+K-1,K-1))%mod;
                ans %= mod;
            }
        }
        else low[u] = min(low[u],dfn[p->v]);
    }
}

int main()
{
    init();
    scanf("%d%d%d",&n,&m,&K);
    for(int i = 1,u,v; i <= m; i++){
        scanf("%d%d",&u,&v);
        add(u,v);   add(v,u);
        get_rev(u,v);
    }
    for(int i = 1; i <= n; i++)
        if(!dfn[i]) tarjan(i);
    printf("%lld\n",ans);
    return 0;
}

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转载自blog.csdn.net/qq_18869763/article/details/81981348
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