线程池原理--执行器AbstractExecutorService

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线程池原理–总索引

线程池原理–执行器AbstractExecutorService

AbstractExecutorService

AbstractExecutorService是一个抽象类，实现自ExecutorService接口。该类实现了接口中的一些方法。

Sumit

可以看到，不管提交的是Runnable类型或者Callable类型的任务，最终都是创建FutureTask类型对象，并提交给execute()方法执行，execute()方法由子类实现。

 public Future<?> submit(Runnable task) {
        if (task == null) throw new NullPointerException();
        RunnableFuture<Void> ftask = newTaskFor(task, null);
        execute(ftask);
        return ftask;
    }
    public <T> Future<T> submit(Runnable task, T result) {
        if (task == null) throw new NullPointerException();
        RunnableFuture<T> ftask = newTaskFor(task, result);
        execute(ftask);
        return ftask;
    }
    public <T> Future<T> submit(Callable<T> task) {
        if (task == null) throw new NullPointerException();
        RunnableFuture<T> ftask = newTaskFor(task);
        execute(ftask);
        return ftask;
    }
    protected <T> RunnableFuture<T> newTaskFor(Runnable runnable, T value) {
        return new FutureTask<T>(runnable, value);
    }
     protected <T> RunnableFuture<T> newTaskFor(Callable<T> callable) {
        return new FutureTask<T>(callable);
    }

批量提交任务

invokeAll 用于批量提交任务，该方法会阻塞，来看一下其实现原理。
如果发生任何异常，所有的任务都会被取消。

 public <T> List<Future<T>> invokeAll(Collection<? extends Callable<T>> tasks)
        throws InterruptedException {
        if (tasks == null)
            throw new NullPointerException();
        ArrayList<Future<T>> futures = new ArrayList<>(tasks.size());
        try {
             // 循环提交任务给execute()
            for (Callable<T> t : tasks) {
                RunnableFuture<T> f = newTaskFor(t);
                futures.add(f);
                execute(f);
            }
            //循环检测所有任务是否执行完毕
            for (int i = 0, size = futures.size(); i < size; i++) {
                Future<T> f = futures.get(i);
                //在这里阻塞一直到f的任务执行完毕。
                if (!f.isDone()) {
                    try { f.get(); }
                    catch (CancellationException ignore) {}
                    catch (ExecutionException ignore) {}
                }
            }
            return futures;
        } catch (Throwable t) {
            cancelAll(futures);
            throw t;
        }
    }

doInvokeAny也是用于批量提交任务，也会发生阻塞，但是只要有一个任务执行完毕，那么便会退出阻塞状态并返回。
并且如果发生任何异常，所有的任务都会被取消。

private <T> T doInvokeAny(Collection<? extends Callable<T>> tasks,
                              boolean timed, long nanos)
        throws InterruptedException, ExecutionException, TimeoutException {
        if (tasks == null)
            throw new NullPointerException();
        //记录当前未提交的任务数量
        int ntasks = tasks.size();
        if (ntasks == 0)
            throw new IllegalArgumentException();
        ArrayList<Future<T>> futures = new ArrayList<>(ntasks);
        ExecutorCompletionService<T> ecs =
            new ExecutorCompletionService<T>(this);

        // For efficiency, especially in executors with limited
        // parallelism, check to see if previously submitted tasks are
        // done before submitting more of them. This interleaving
        // plus the exception mechanics account for messiness of main
        // loop.

        try {
            // Record exceptions so that if we fail to obtain any
            // result, we can throw the last exception we got.
            ExecutionException ee = null;
            final long deadline = timed ? System.nanoTime() + nanos : 0L;
            Iterator<? extends Callable<T>> it = tasks.iterator();

            // Start one task for sure; the rest incrementally
            //提交第一个任务
            futures.add(ecs.submit(it.next()));
            //每提交第一个任务，ntasks-1
            --ntasks;
            int active = 1;

            for (;;) {
            //检索并移除下一个要完成的任务
                Future<T> f = ecs.poll();
                //f == null ，说明还没有任务要完成，继续添加任务执行
                if (f == null) {
                    if (ntasks > 0) {
                        --ntasks;
                        futures.add(ecs.submit(it.next()));
                        ++active;
                    }
                    else if (active == 0)
                        break;
                        //超时判断处理
                    else if (timed) {
                        f = ecs.poll(nanos, NANOSECONDS);
                        if (f == null)
                            throw new TimeoutException();
                        nanos = deadline - System.nanoTime();
                    }
                    else
                        f = ecs.take();
                }
                //f！= null ，说明已经有任务完成，返回结果
                if (f != null) {
                    --active;
                    try {
                        return f.get();
                    } catch (ExecutionException eex) {
                        ee = eex;
                    } catch (RuntimeException rex) {
                        ee = new ExecutionException(rex);
                    }
                }
            }

            if (ee == null)
                ee = new ExecutionException();
            throw ee;

        } finally {
            cancelAll(futures);
        }
    }