leetcode 2. 两数相加 C语言版

struct ListNode* addTwoNumbers(struct ListNode* l1, struct ListNode* l2) {
    struct ListNode* l = (struct ListNode*)malloc(sizeof(struct ListNode));
    struct ListNode* p = l1,* q = l2, * t = l;
    t->val = 0;
    t->next = NULL;
    while(p != NULL&&q != NULL)
    {
        struct ListNode* node = (struct ListNode*)malloc(sizeof(struct ListNode));
        node->val = 0;
        node->next = NULL;
        t->next = node;
        t->val += (p->val + q->val);
        if(t->val >= 10)
        {
            t->val -= 10;
            node->val = 1;
        }
        p = p->next;
        q = q->next;
        if(p == NULL&&q == NULL&&t->next->val == 0)     //防止最后出现一个0
            t->next = NULL;
        t = t->next;
    }
    while(p != NULL)    //l1未结束而l2结束了
    {
        struct ListNode* node = (struct ListNode*)malloc(sizeof(struct ListNode));
        node->val = 0;
        node->next = NULL;
        t->next = node;
        t->val += p->val;
        if(t->val >= 10)
        {
            t->val -= 10;
            node->val = 1;
        }
        p = p->next;
        if(p == NULL&&t->next->val == 0)
            t->next = NULL;
        t = t->next;
    }
    while(q != NULL)    //l2未结束而l1结束了
    {
        struct ListNode* node = (struct ListNode*)malloc(sizeof(struct ListNode));
        node->val = 0;
        node->next = NULL;
        t->next = node;
        t->val += q->val;
        if(t->val >= 10)
        {
            t->val -= 10;
            node->val = 1;
        }
        q = q->next;
        if(q == NULL&&t->next->val == 0)
            t->next = NULL;
        t = t->next;
    }
    return l;
}

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转载自blog.csdn.net/ASZZY/article/details/83046388