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● 数据结构
ArrayList基于动态数组;LinkedList基于链表
● 随机访问
ArrayList优于LinkedList,因为LinkedList要移动指针来查找,下面以get方法为例
//ArrayList的get方法,直接从数组中获取元素值
public E get(int index) {
if (index < 0 || index >= this.size)
throw new IndexOutOfBoundsException(outOfBoundsMsg(index));
if (ArrayList.this.modCount != this.modCount)
throw new ConcurrentModificationException();
return (E) ArrayList.this.elementData[offset + index];
}
//LinkedList的get方法,node方法用来进行查找
public E get(int index) {
checkElementIndex(index);
return node(index).item;
}
Node<E> node(int index) {
if (index < (size >> 1)) {//若index小于size的一半,则从头开始查找
Node<E> x = first;
for (int i = 0; i < index; i++)
x = x.next;
return x;
} else {//若index大于size的一半,则从末尾向前开始查找
Node<E> x = last;
for (int i = size - 1; i > index; i--)
x = x.prev;
return x;
}
}
● 插入删除
1. 末尾插入,两个的时间复杂度都是O(1),所以差不多 [删除操作也同理]
//ArrayList的add方法
public boolean add(E e) {
ensureCapacityInternal(size + 1); // Increments modCount!!
elementData[size++] = e;
return true;
}
//LinkedList的add方法
public boolean add(E e) {
linkLast(e);
return true;
}
void linkLast(E e) {
final Node<E> l = last;
final Node<E> newNode = new Node<>(l, e, null);
last = newNode;
if (l == null)
first = newNode;
else
l.next = newNode;
size++;
modCount++;
}
2. 中间插入,时间复杂度也都是O(n),所以也差不多 [删除操作也同理]
//ArrayList的add方法
public void add(int index, E element) {
if (index > size || index < 0)
throw new IndexOutOfBoundsException(outOfBoundsMsg(index));
ensureCapacityInternal(size + 1); // Increments modCount!!
System.arraycopy(elementData, index, elementData, index + 1,
size - index);//index后面的元素后移,时间复杂度O(n)
elementData[index] = element;
size++;
}
//LinkedList的add方法
public void add(int index, E element) {
checkPositionIndex(index);
if (index == size) //index等于size时,直接链接到末尾
linkLast(element);
else //否则直接将element链接到node(index)前面,node(index)的时间复杂度也是O(n)
linkBefore(element, node(index));
}
void linkLast(E e) {
final Node<E> l = last;
final Node<E> newNode = new Node<>(l, e, null);
last = newNode;
if (l == null)
first = newNode;
else
l.next = newNode;
size++;
modCount++;
}
void linkBefore(E e, Node<E> succ) {
// assert succ != null;
final Node<E> pred = succ.prev;
final Node<E> newNode = new Node<>(pred, e, succ);
succ.prev = newNode;
if (pred == null)
first = newNode;
else
pred.next = newNode;
size++;
modCount++;
}