数组-约瑟夫环

题目描述:

已知有n个人围坐在一张圆桌上,编号依次为0,1,2,...n-1, 编号为n-1与编号为0的人坐在相邻的位置。现在编号为k的人从1开始报数,数到m的那个人会退出圆桌。他的下一个人又从1开始报数,数到m的那个人又出列。依此规律重复下去,请问最后出列的人的编号。

输入格式:

输入一行,包含三个整数n,k,m

输出格式:

输出一行,包含一个整数

#include<iostream>
using namespace std;

struct node
{
	int date;
	node *next;
};

class linklist
{
public:
	linklist()
	{
		node *p = new node();
		p->date = 1;
		p->next = p;
		first = p;
	};
	void josephus(int n,int k,int m);
 
private:
	node *first;
};

void linklist::josephus(int n, int k, int m)
{
	node *p=first;
	for (int i = 2; i < n+1; i++)
	{
		node *q = new node();
		q->date = i;
		q->next = p->next;
		p->next = q;
		p = q;
	}
	//数到第k个节点,使其为当前节点
	p = first;
	node *temp = p;            //这个temp初始值保证了第一次开始计数到m的第一个元素与其后各循环 
                               删除元素起始点不一致情况下,循环体可正常运行。
	while (--k)
		p = p->next;
	
	while (n--)
	{
		for (int i = 1; i < m; i++)
		{
			temp = p;
			p = p->next;
		}
		//cout << p->date<<"   ";
		temp->next = p->next;
		p = temp->next;
	}
	cout << p->date;
	cout <<endl;
}

int main()
{
	int n , k , m ;
	cin >> n >> k >> m;
	linklist L;
	L.josephus(n, k, m);
	//system("pause");

	return 0;
}



 在网上看到其他网友的写法:

include <iostream>
using namespace std;
 
struct MyNode
{
    MyNode(int a_data):m_data(a_data),m_pNext(NULL) {}    
    int    m_data;
    MyNode *m_pNext;
};
 
class Josephus
{
public:
    Josephus(int a_N, int a_K, int a_M):m_N(a_N),m_K(a_K),m_M(a_M)
    {
        createList();
        outputList();
    }    
protected:
    void createList();
    void outputList();    
private:
    MyNode *m_pHead;//循环链表的头节点
    int    m_N;     //链表节点个数
    int    m_K;     //第一个报数人的序号
    int    m_M;     //报数出局的数
};
void Josephus::createList()
{
    MyNode *pre = NULL;
    MyNode *cur = NULL;
    MyNode *p = new MyNode(1);
    m_pHead = p;
    cur = p;
    for (int i=2; i<=m_N; i++)
    {
        p = new MyNode(i);
        pre = cur;
        cur = p;
        pre->m_pNext = cur;
    }
    cur->m_pNext = m_pHead;    
    int n=m_N;
    p = m_pHead;
    while (n--)
    {
        cout << p->m_data << ",";
        p = p->m_pNext;
    }
    cout << endl;
}
 
void Josephus::outputList()
{
    MyNode *pre = NULL;
    MyNode *cur = m_pHead;
    m_K;
    while (m_K--)            //寻找第K个人(开始报数的人)
    {
        pre = cur;
        cur = cur->m_pNext;
    }
    while (m_N--)            //输出链表中所有的节点值
    {
        int s = m_M-1;
        while (s--)            //寻找间隔M的人
        {
            pre = cur;
            cur = cur->m_pNext;
        }
        MyNode *p = cur;
        cout << p->m_data << ",";
        cur = cur->m_pNext;    //删除节点的过程
        pre->m_pNext = cur;
        delete p;
        p=NULL;
    }
}
 
int main()
{
    Josephus josephus(4,1,3);
    return 0;
}

猜你喜欢

转载自blog.csdn.net/weixin_40539125/article/details/82878022
今日推荐