（约瑟夫环）

题

Let’s play a stone removing game.
Initially, n stones are arranged on a circle and numbered 1, . . . , n clockwise (Figure 1). You are also
given two numbers k and m. From this state, remove stones one by one following the rules explained
below, until only one remains. In step 1, remove stone m. In step 2, locate the k-th next stone clockwise
from m and remove it. In subsequent steps, start from the slot of the stone removed in the last step,
make k hops clockwise on the remaining stones and remove the one you reach. In other words, skip
(k − 1) remaining stones clockwise and remove the next one. Repeat this until only one stone is left
and answer its number.
For example, the answer for the case n = 8, k = 5, m = 3 is 1, as shown in Figure 1.
Figure 1: An example game
Initial state: Eight stones are arranged on a circle.
Step 1: Stone 3 is removed since m = 3.
Step 2: You start from the slot that was occupied by stone 3. You skip four stones 4, 5, 6 and 7
(since k = 5), and remove the next one, which is 8.
Step 3: You skip stones 1, 2, 4 and 5, and thus remove 6. Note that you only count stones that
are still on the circle and ignore those already removed. Stone 3 is ignored in this case.
Steps 4-7: You continue until only one stone is left. Notice that in later steps when only a few
stones remain, the same stone may be skipped multiple times. For example, stones 1 and 4 are skipped
twice in step 7.
Final State: Finally, only one stone, 1, is on the circle. This is the final state, so the answer is 1.

Input

The input consists of multiple datasets each of which is formatted as follows.
n k m
The last dataset is followed by a line containing three zeros. Numbers in a line are separated by a
single space. A dataset satisfies the following conditions.
2 ≤ n ≤ 10000, 1 ≤ k ≤ 10000, 1 ≤ m ≤ n
The number of datasets is less than 100.

Output

For each dataset, output a line containing the stone number left in the final state. No extra characters
such as spaces should appear in the output.

Sample Input

8 5 3
100 9999 98
10000 10000 10000
0 0 0

Sample Output

1
93
2019

翻译

n个人，从1开始数，数到数字k就淘汰，m为第一个淘汰人，问最后剩下的一个人为谁

代码

//我没搞懂，就当样板记了
#include "stdio.h"
#include "string.h"
int a[100009];
int main()
{
    
    
	int i,j,l;
	int n,k,m;
	while(~scanf("%d%d%d",&n,&k,&m)&&(n+k+m)!=0)
	{
    
    
		memset(a,0,sizeof(a));
		for(i=2;i<n;i++)
			a[i]=(a[i-1]+k)%i;
		j=(a[i-1]+m+1)%n;
		if(j<=0)
		j+=n;
		printf("%d\n",j); 
	}
}