POJ 1330 Nearest Common Ancestors (LCA模板题)

题目链接:http://poj.org/problem?id=1330

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

#define debug puts("YES");
#define rep(x,y,z) for(int (x)=(y);(x)<(z);(x)++)
#define read(x,y) scanf("%d%d",&x,&y)
#define ll long long

#define lrt int l,int r,int rt
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define root l,r,rt
const int  maxn =1e5+5;
const int mod=1e9+7;
const ll INF =1e18+7;
ll powmod(ll x,ll y){ll t; for(t=1;y;y>>=1,x=x*x%mod) if(y&1) t=t*x%mod; return t;}
ll gcd(ll x,ll y){return y?gcd(y,x%y):x;}

int d[maxn];
///链式前向星
struct edge
{
    int u,nxt;
    edge(){}
    edge(int x,int y)
    {
        u=x,nxt=y;
    }
}e[maxn<<1];
int head[maxn],tot=0;
void init(){tot=0;memset(head,-1,sizeof(head));}
void add(int x,int y)
{
    e[tot]=edge(y,head[x]);
    head[x]=tot++;
}

int res,p1,p2,fa[maxn];
int Find(int x){return x==fa[x]?x:fa[x]=Find(fa[x]);}
void tarjan(int u)///离线算法的模板
{
    fa[u]=u;
    for(int i=head[u];~i;i=e[i].nxt)
    {
        int v=e[i].u;
        tarjan(v);
        fa[v]=u;
    }
    if(u==p1||u==p2)
    {
        if(u!=p1) swap(p1,p2);
        if(fa[p2]) res=Find(fa[p2]);
    }
}

int n,u,v;

int main()
{
    int t;scanf("%d",&t);
    while(t--)
    {
        init();  scanf("%d",&n);
        memset(d,0,sizeof(d));
        memset(fa,0,sizeof(fa));
        for(int i=0;i<n-1;i++)
        {
            scanf("%d%d",&u,&v);
            add(u,v);  d[v]++;
        }
        scanf("%d%d",&p1,&p2);
        for(int i=1;i<=n;i++)  if(d[i]==0) {tarjan(i);printf("%d\n",res);break;}
    }
    return 0;
}

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转载自blog.csdn.net/qq_37451344/article/details/82909122
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