=== Op tech briefing, 2002/11/02 06:42 CST ===
“The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein’s secrets and wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters, usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, …, Z=26). The combination is then vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary.”
v - w^2 + x^3 - y^4 + z^5 = target
“For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn’t exist then.”
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
“Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or ‘no solution’ if there is no correct combination. Use the exact format shown below.”
Input
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
Output
LKEBA
YOXUZ
GHOST
no solution
Sample Input
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
Sample Output
LKEBA
YOXUZ
GHOST
no solution
一直在漫无目的的找题做，可是回头想想，把原来的题都做明白了就很好了，然后回头整理一下原来做的题，也给自己的博客多点文章（(▽)）。
题意：给你一个数和一串字符串，问能不能在这串字符串中找出一串来根据他给的式子得到最初的那个数。长度为4。典型的深搜dfs，快速幂的那个地方建议自己写，那个pow函数比较慢。
代码给上：
#include
#include
#include
#define ll long long
using namespace std;
int len;
ll n;
char a[1010];
char b[1010];
char c[1010];
int vis[1010];
int qsm(int n,int m)
{
int t=1;
while(m)
{
if(m%2)
t*=n;
m/=2;
n*=n;
}
return t;
}
void dfs(int step)
{
if(step5)
{
b[5]=’\0’;
ll m=qsm(b[0]-‘A’+1,1)-qsm(b[1]-‘A’+1,2)+qsm(b[2]-‘A’+1,3)-qsm(b[3]-‘A’+1,4)+qsm(b[4]-‘A’+1,5);
if(mn)
{
if(strcmp(b,c)>0)
{
strcpy(c,b);
}
}
return;
}
for(int i=0;i<len;i++)
{
if(!vis[i])
{
vis[i]=1;
b[step]=a[i];
dfs(step+1);
vis[i]=0;
}
}
}
int main()
{
while(cin>>n>>a)
{
if(n==0&&strcmp(a,“END”)==0) break;
len=strlen(a);
memset(vis,0,sizeof(vis));
memset(c,’\0’,sizeof©);
dfs(0);
if(strlen©==0)
cout<<“no solution”<<endl;
else cout<<c<<endl;
}
return 0;
}
努力加油a啊，(o)/~