10. Regular Expression Matching(正则表达式)

Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'.

'.' Matches any single character.
'*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

Note:

s could be empty and contains only lowercase letters a-z.
p could be empty and contains only lowercase letters a-z, and characters like . or *.

Example 1:

Input:
s = "aa"
p = "a"
Output: false
Explanation: "a" does not match the entire string "aa".

Example 2:

Input:
s = "aa"
p = "a"
Output: true
Explanation: '
' means zero or more of the precedeng element, 'a'. Therefore, by repeating 'a' once, it becomes "aa".

Example 3:

Input:
s = "ab"
p = "."
Output: true
Explanation: ".
" means "zero or more (*) of any character (.)".

Example 4:

Input:
s = "aab"
p = "cab"
Output: true
Explanation: c can be repeated 0 times, a can be repeated 1 time. Therefore it matches "aab".

Example 5:

Input:
s = "mississippi"
p = "misisp*."
Output: false

Solution1:

import re
class Solution:
    def isMatch(self, s, p):
        """
        :type s: str
        :type p: str
        :rtype: bool
        """
        return re.match(p + '$',s)!=None

Solution2:

import re
class Solution:
    def isMatch(self, s, p):
        """
        :type s: str
        :type p: str
        :rtype: bool
        """
        return re.search('^' + p + '$',s)!=None

'^'表示匹配字符串开头,'$'表示匹配字符串结尾。
re.match只匹配字符串的开始,如果字符串开始不符合正则表达式,则匹配失败,函数返回None;而re.search匹配整个字符串,直到找到一个匹配。

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转载自www.cnblogs.com/bernieloveslife/p/9745342.html
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