习题 4-1 古老的密码

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#include<iostream>
#include<cstring>
#include<algorithm> 
using namespace std;
char s1[105];
char s2[105];
int cnt1[26];
int cnt2[26];

bool compare(int a,int b){
	return a>b;
}
int f(char c){
	return (int)c-'A';
}
int main(){
	cin>>s1>>s2;
	memset(cnt1,0,sizeof(cnt1));
	memset(cnt2,0,sizeof(cnt2));
	for(int i=0;i<strlen(s1);i++){
		int n1=f(s1[i]);
		int n2=f(s2[i]);
		cnt1[n1]++;
		cnt2[n2]++;
	}
	sort(cnt1,cnt1+26,compare);
	sort(cnt2,cnt2+26,compare);
	
	bool flag=true;
	for(int i=0;i<26;i++){
		if(cnt1[i]!=cnt2[i]){
			flag=false;
		}
		if(cnt1[i]==0&&cnt2[i]==0)
			break;
	}
	if(flag)
		cout<<"YES"<<endl;
	else
		cout<<"NO"<<endl;
	return 0;
}

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转载自blog.csdn.net/qq_41138935/article/details/82761829
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