c语言:矩阵相乘-矩阵相加 新手练习1

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<string.h>
void main()
{
     int a[4][4];
     int b[4][4];
     int c[4][4];
     int i,j,k,s,t,m,n;
     srand(time(0));
     for(i=0;i<=3;i++)
         for(j=0;j<=3;j++)
             a[i][j]=rand()%20+1;
                 printf("a is \n");
                 for(i=0;i<=3;i++)
                 {
                 
                     for(j=0;j<=3;j++)
                         
                         
                             printf("%5d",a[i][j]);
                                 printf("\n");
                                     printf("\n");
             }
                         
                             for(i=0;i<=3;i++)
                             for(j=0;j<=3;j++)
                                 b[i][j]=rand()%20+1;
                                 printf("b is \n");
                                             for(i=0;i<=3;i++)
                                             {
                                             
                                             for(j=0;j<=3;j++)
                                             
                                                 
                                                 printf("%5d",b[i][j]);
                                                     printf("\n");
                                                         printf("\n");
                                             }
                                                 for(i=0;i<=3;i++)
                                                     for(j=0;j<=3;j++)
                                                         c[i][j]=a[i][j]+b[i][j];
                                                             printf("c is \n");
                                                             
                                                                 for(i=0;i<=3;i++)
                                             {
                                             
                                             for(j=0;j<=3;j++)
                                             
                                                 
                                                 printf("%5d",c[i][j]);
                                                     printf("\n");
                                                         printf("\n");
                                             }
                                             int z;
                                             z=0;
                                     printf("a is \n");
                                         for(i=0;i<=3;i++)
                 {
                 
                     for(j=0;j<=3;j++)
                         
                         
                             printf("%5d",a[i][j]);
                                 printf("\n");
                                     printf("\n");
             }
 
                             int my=0;
                             int sb=0;
                             k=0;
                             int jsq=0;
                                                             printf("my is : \n");
                                     for(k=0;k<=3;k++)
                                     {
                                         for(i=0;i<=3;i++)
                                     {
                                     
                                     for(j=0;j<=3;j++)
                                     {
                                 
                                     sb=a[k][j]*b[j][i];
                                     my=my+sb;
                                     
                                     }
                                     c[k][i]=my;
         
                                     printf("%5d",c[k][i]);
                                     jsq++;
                                     if(jsq%4==0)
                                     printf("\n");
                                     my=0;
                                 }
                             }                                                      
                              }

猜你喜欢

转载自www.cnblogs.com/jx3ajmd/p/9610398.html
今日推荐