[USACO15FEB]Superbull (最小生成树)

题目链接


Solution

基本上就是个板子.
因为 \(n\) 很小,只有 \(2000\),所以直接暴力建图,然后跑最小生成树就好了.

Code

#include<bits/stdc++.h>
#define ll long long
using namespace std;
const int maxn=2008;
struct sj{
  int to,fr; ll w;
}a[maxn*maxn];
int fa[maxn],num[maxn];
int n,cnt;
ll w[maxn],ans;

ll read()
{
    char ch=getchar(); ll f=1,w=0;
    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    while(ch<='9'&&ch>='0'){w=w*10+ch-'0';ch=getchar();}
    return f*w;
}

bool cmp(sj x,sj y)
{return x.w>y.w;}

int find(int x)
{
    if(fa[x]==x)return x;
    else return fa[x]=find(fa[x]);
}

void join(int x,int y)
{
    x=find(x),y=find(y);
    if(num[x]>num[y])swap(x,y);
    if(x!=y)fa[x]=y;
    num[y]+=num[x]; num[x]=0;
}

int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    w[i]=read(),fa[i]=i;
    for(int i=1;i<=n;i++)
    for(int j=i+1;j<=n;j++)
    a[++cnt].fr=i,a[cnt].to=j,a[cnt].w=w[i]^w[j];
    sort(a+1,a+cnt+1,cmp);
    for(int i=1;i<=cnt;i++)
    {
        int x=a[i].fr,y=a[i].to;
        if(find(x)!=find(y))
        join(x,y),ans+=a[i].w;
    }
    cout<<ans<<endl;
}

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转载自www.cnblogs.com/Kv-Stalin/p/9577320.html