PAT：1082. Read Number in Chinese (25)

版权声明：本文为博主原创文章，未经博主允许不得转载。 https://blog.csdn.net/dpdpd/article/details/51569431

参考网上的代码，感觉逻辑性很强，值得自己学习

#include<stdio.h>
#include<iostream>
#include<cstring>
#include<string.h>
#include<string>
#include<algorithm>
#include <vector>
#include<cmath>
using namespace std;
int main() 
{
    string str;
    cin>>str;
    string sz[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    string x[9]={"","Shi","Bai","Qian","Wan","Shi","Bai","Qian","Yi"};
    if(str[0]=='-')
    {
        cout<<"Fu ";
        str=str.substr(1);
    }
    reverse(str.begin(),str.end());;//倒转过来；
    int flag=0;
    for(int i=str.size()-1;i>0;i--)
    {
        if(i==str.size()-1)
        {
            cout<<sz[str[i]-'0'];
            cout<<" "<<x[i];
        }
        else
        {
            if(str[i]!='0')
            {
                if(flag==1)
                {
                    flag=0;
                    cout<<" "<<sz[0];
                }
                cout<<" "<<sz[str[i]-'0'];
                cout<<" "<<x[i];
            }
            else
            {
                flag=1;
                if(i==4)
                    cout<<" "<<x[4];
            }
        }
    }
    if(flag==1&&str[0]!='0')
        cout<<" ling";
    if(str.size()==1)
        cout<<sz[str[0]-'0'];
    else if(str.size()>1&&str[0]!='0')
        cout<<" "<<sz[str[0]-'0'];
    return 0;
}