Lweb has a string SS.
Oneday, he decided to transform this string to a new sequence.
You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).
You need transform every letter in this string to a new number.
AA is the set of letters of SS, BB is the set of natural numbers.
Every injection f:A→Bf:A→B can be treat as an legal transformation.
For example, a String “aabc”, A={a,b,c}A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.
Now help Lweb, find the longest LIS which you can obtain from SS.
LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)
Input
The first line of the input contains the only integer T,(1≤T≤20)T,(1≤T≤20).
Then TT lines follow, the i-th line contains a string SS only containing the lowercase letters, the length of SS will not exceed 105105.
Output
For each test case, output a single line "Case #x: y", where x is the case number, starting from 1. And y is the answer.
Sample Input
2 aabcc acdeaa
Sample Output
Case #1: 3 Case #2: 4
#include <iostream>
#include<stdio.h>
#include<algorithm>
#include<string.h>
using namespace std;
int main()
{
int t;
cin>>t;
int p=0;
while(t--)
{
string s;
cin>>s;
int sum=0;
int n=s.size();
int i;
int a[100010];
memset(a,0,sizeof(a));
for(i=0; i<n; i++)
{
int x=s[i]-'0';
if(a[x]==0)
{a[x]=1;
sum++;
}
}
p++;
printf("Case #%d: %d\n",p,sum);
}
return 0;
}