项目中用到rocket mq的方式有多种,
第一种,严格按照时间消费的模式,这种模式需要用串行方式,生产者生产的时候,这时候生产者需要往特定的队列里有序push:
SendResult result = producer.send(msg, new MessageQueueSelector(){
@Override
public MessageQueue select(List<MessageQueue> mqs, Message msg, Object arg) {
Integer id = arg.hashCode();
int index = id % mqs.size();
return mqs.get(index);
}
}, dataAsyncEvent.getDataType());
消费者也要按照顺序严格有序消费,用这个有序的监听者:
//同一队列的消息同一时刻只能一个线程消费,可保证消息在同一队列严格有序消费
consumer.registerMessageListener(new MessageListenerOrderly() {
@Override
public ConsumeOrderlyStatus consumeMessage(List<MessageExt> msgs,
ConsumeOrderlyContext context) {
return ConsumeOrderlyStatus.CONSUME_SUCCESS;
}
public interface MessageListenerOrderly extends MessageListener {
/**
* 方法抛出异常等同于返回 ConsumeOrderlyStatus.SUSPEND_CURRENT_QUEUE_A_MOMENT<br>
* P.S: 建议应用不要抛出异常
*
* @param msgs
* msgs.size() >= 1<br>
* DefaultMQPushConsumer.consumeMessageBatchMaxSize=1,默认消息数为1
* @param context
* @return
*/
public ConsumeOrderlyStatus consumeMessage(final List<MessageExt> msgs,
final ConsumeOrderlyContext context);
}
第二种:不追求时间顺序,只要把生产出来的事件全部消费完就可以。这种可以用并行的方式处理,效率高很多:
生产者:
SendResult result = producer.send(msg);
消费者:(用此接口处理)
consumer.registerMessageListener(new MessageListenerConcurrently() {
@Override
public ConsumeConcurrentlyStatus consumeMessage(List<MessageExt> msgs,
ConsumeConcurrentlyContext context) {
return ConsumeConcurrentlyStatus.CONSUME_SUCCESS;
}
public interface MessageListenerConcurrently extends MessageListener {
/**
* 方法抛出异常等同于返回 ConsumeConcurrentlyStatus.RECONSUME_LATER<br>
* P.S: 建议应用不要抛出异常
*
* @param msgs
* msgs.size() >= 1<br>
* DefaultMQPushConsumer.consumeMessageBatchMaxSize=1,默认消息数为1
* @param context
* @return
*/
public ConsumeConcurrentlyStatus consumeMessage(final List<MessageExt> msgs,
final ConsumeConcurrentlyContext context);
}
http://blog.csdn.net/fangletian1981/article/details/20694381