u Calculate e
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
———–
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
#include <stdio.h>
int main ()
{
int i;
printf("n e\n");
printf("- -----------\n");
printf("0 1\n");
printf("1 2\n");
printf("2 2.5\n");
double result = 2.5 ;
double p = 0.5;
for(i = 3; i <= 9; ++ i ) //根据公式计算即可
{
p /= i;
result += p;
printf("%d %.9f\n", i , result);
}
return 0;
}