HDOJ--1012 u Calculate e

原题链接

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333

 

第1 2 3 个特殊解法

#include<stdio.h>

int main()
{
	int i,n,temp;
	double result=2.5;temp=2;
	printf("n e\n- -----------\n");
	printf("0 1\n");
	printf("1 2\n");
	printf("2 2.5\n");
	for(i=3;i<=9;i++)
	{
		temp*=i;
		result=result+1.0/temp;
		printf("%d %.9lf\n",i,result);
	}
	return 0;
}