Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:
27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 |
128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 |
Input
The input will have a number N (1 <= N <= 9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
4
00000000000000000000000000000000
00000011100000001111111111111111
11001011100001001110010110000000
01010000000100000000000000000001
Sample Output
0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1
#include <iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
int T;
char s;
scanf("%d",&T);
while(T--)
{
int sum;
int a[8]={128,64,32,16,8,4,2,1};
for(int i=0;i<4;i++)
{
sum=0;
for(int j=0;j<8;j++)
{
cin>>s;
s-='0';
if(s)
sum+=a[j];
}
if(i!=0)
printf(".");
printf("%d",sum);
}
printf("\n");
}
return 0;
}