Problem E. Easy Arithmetic

AC代码（-1001输出是-1+0+0+1；-1100的输出是-1+100）

Select Code

#include <bits/stdc++.h>
#include <iostream>
using namespace std;

int main()
{
   freopen("easy.in", "r", stdin);
    freopen("easy.out","w",stdout);
    char a[1000+10];
    int  i = 0;
    cin>>a;
     while(a[i]!='\0')
    {
        if(a[i]=='-')
        {
            printf("%c",'-');
            i++;
            printf("%c",a[i]);
            i++;
            while(a[i]=='0'&&a[i]!='\0')
            {
                printf("%c%c",'+', '0');
                i++;
            }
            if(a[i]>'0'&&a[i]<='9')
            {
                printf("%c",'+');
                while(a[i]!='+'&&a[i]!='-'&&a[i]!='\0')
                {
                    printf("%c",a[i]);
                    i++;
                }
            }
        }
        else
        {
            printf("%c",a[i]);
            i++;
        }
    }
    printf("\n");
    return 0;
}