[转]关于JAVA中执行static块与构造函数的先后顺序

package com.zwgt;

/**
 * <p>Title: </p>
 *
 * <p>Description: </p>
 *
 * <p>Copyright: Copyright (c) 2007</p>
 *
 * <p>Company: </p>
 *
 * @author not attributable
 * @version 1.0
 */
public class Prize {
    public Prize() {
        try {
            jbInit();
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }

    public static void main(String args[]) {
        childclass child = new childclass();//看看程序的运行结果?
    }

    private void jbInit() throws Exception {
    }
}


class superclass {

    public superclass() {
        System.out.println("this is superclass construct function()");
    }

    static {

        System.out.println("this is superclass static {}");

    }


}


class childclass extends superclass {

    public childclass() {
        System.out.println("this is childclass construct function()");
    }

    static {

        System.out.println("this is childclass static {}");

    }


}
/*
 打印结果如下:
 this is superclass static {}
 this is childclass static {}
 this is superclass construct function()
 this is childclass construct function()
 由此可以看出:程序先执行静态块,然后执行相应的构造函数
 如果子类在实例化时,首先执行父类的static{},然后执行子类的static{},然后执行父类的构造函数,最后执行子类的构造函数
 */

文章转自:http://blog.sina.com.cn/s/blog_4c6fef6301000ch7.html

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