Python实现括弧匹配算法

from pythonds.basic.stack import Stack
# 算法一实现括弧匹配，利用栈来实现
def parCheck(symbolString):
	s = Stack()
	balanced = True
	index = 0

	while index < len(symbolString) and balanced:
		symbol = symbolString[index]
		if symbol == '(':
			s.push(symbol)
		else:
			if s.isEmpty():
				balanced = False
			else:
				s.pop()

		index += 1

	if balanced and s.isEmpty():
		return True
	else:
		return False

def match(open, close):
	opens = "([{"
	closers = ")]}"
	return opens.index(open) == closers.index(close)
# 算法二实现（ 【 { } 】 ）都能进行匹配
def parCheck2(symbolString):
	s = Stack()
	balanced = True
	index = 0

	while index < len(symbolString) and balanced:
		symbol = symbolString[index]
		if symbol in '([{':
			s.push(symbol)
		else:
			if s.isEmpty():
				balanced = False
			else:
				top = s.pop()
				if not match(top, symbol):
					balanced = False

		index += 1

	if balanced and s.isEmpty():
		return True
	else:
		return False

if __name__ == '__main__':

	s = Stack()
	print(s.isEmpty())
	s.push(4)
	s.push('dog')
	print(s.peek())
	s.push(True)
	print(s.size())
	print(s.isEmpty())
	s.push(8.4)
	print(s.pop())
	print(s.pop())
	print(s.size())

	print('--------------------------')

	print(parCheck('(((())))'))
	print(parCheck2('(((([]))))'))