Java并行程序设计——求九位自幂数个数（Thread类实现）

【项目说明】：继承Thread类实现求九位自幂数个数的Java多线程并行程序

求九位自幂数个数并输出结果、串行、并行时间、以及加速比。

【项目代码】：

/**继承Thread类实现求九位自幂数个数的Java多线程并行程序*/
public class And extends Thread {
    private  long start;
    private  long sum=0;    
    
    public And(long start) {
        super();
        this.start = start;
    }	
	
    public void run() {
    	long a,b,c,d,e,f,g,h;
   	 for( a=start; a<=9; a+=2)
   	        for( b=0; b<=9; b++)
   	            for(c=0; c<=9; c++)
   	                for(d=0; d<=9; d++)
   	                    for(e=0; e<=9; e++)
   	                        for(f=0; f<=9; f++)
   	                            for(g=0; g<=9; g++)
   	                                for(h=0; h<=9; h++)
   	                                    if(a*10000000+b*1000000+c*100000+d*10000+e*1000+f*100+g*10+h==a*a*a*a*a*a*a*a+b*b*b*b*b*b*b*b+c*c*c*c*c*c*c*c+d*d*d*d*d*d*d*d+e*e*e*e*e*e*e*e+f*f*f*f*f*f*f*f+g*g*g*g*g*g*g*g+h*h*h*h*h*h*h*h)
   	                                        sum++;
    }
    public long sum(){
    	long a,b,c,d,e,f,g,h;
   	 for( a=start; a<=9; a++)
   	        for( b=0; b<=9; b++)
   	            for(c=0; c<=9; c++)
   	                for(d=0; d<=9; d++)
   	                    for(e=0; e<=9; e++)
   	                        for(f=0; f<=9; f++)
   	                            for(g=0; g<=9; g++)
   	                                for(h=0; h<=9; h++)
   	                                    if(a*10000000+b*1000000+c*100000+d*10000+e*1000+f*100+g*10+h==a*a*a*a*a*a*a*a+b*b*b*b*b*b*b*b+c*c*c*c*c*c*c*c+d*d*d*d*d*d*d*d+e*e*e*e*e*e*e*e+f*f*f*f*f*f*f*f+g*g*g*g*g*g*g*g+h*h*h*h*h*h*h*h)
   	                                        sum++;      
   	 return sum;
    }

    public long getSum() {
        return sum;
    }

    public static void main(String[] args) throws InterruptedException {
        And thread1=new And(1);
        And thread2=new And(2);
        long startTime=System.currentTimeMillis();	
        thread1.start();
        thread2.start();
        thread1.join();
        thread2.join();
        long endTime=System.currentTimeMillis();
        System.out.println("并行结果="+(thread1.getSum()+thread2.getSum()));
        System.out.println("并行时间="+(endTime-startTime));
        long t1=endTime-startTime;
        startTime=System.currentTimeMillis();
        And serial=new And(1);
        long sum=serial.sum();
        endTime=System.currentTimeMillis();
        System.out.println("串行结果="+sum);
        System.out.println("串行时间="+(endTime-startTime));
        long t2=endTime-startTime;
        System.out.println("加速比="+t2*1.0/t1);
    }
}

【运行截图】：