字符串的排列(剑指offer)

题目:输入一个字符串,按字典序打印出该字符串中字符的所有排列。例如输入字符串abc,则打印出由字符a,b,c所能排列出来的所有字符串abc,acb,bac,bca,cabcba

思路:这是一个全排列问题

采用递归的思想,固定第一个字符,后面的字符也按照递归求解


class Solution:
    def Permutation(self, ss):
        if ss == []:
            return
        if len(ss)==1:
            return list(ss)
        
        sslist = list(ss)
        sslist.sort()

        pstr = [] 
        for i in range(len(sslist)):
            if i>0 and sslist[i]==sslist[i-1]:
                continue
            tmp = self.Permutation(''.join(sslist[:i])+''.join(sslist[i+1:]))           

            for j in tmp:
                pstr.append(sslist[i]+j)
        return pstr
        
a = Solution()
print(a.Permutation('aabc'))

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转载自blog.csdn.net/eat_shopping/article/details/80929975