Search Insert Position(LeetCode)

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example 1:

Input: [1,3,5,6], 5
Output: 2

Example 2:

Input: [1,3,5,6], 2
Output: 1

Example 3:

Input: [1,3,5,6], 7
Output: 4

Example 4:

Input: [1,3,5,6], 0
Output: 0

思路：

二分查找，找到就返回mid，找不到就返回low。

class Solution {
public:
	int searchInsert(vector<int>& nums, int target) {
		int n=nums.size();
		int low=0;
		int high=n-1;
		while(low<=high){
			int mid = low+(high-low)/2;
			if(nums[mid]>target) high=mid-1;
			else if(nums[mid]<target) low=mid+1;
			else return mid;
		}
		return low;
	}
};