# -*- coding:utf-8 -*-
class Solution:
def minNumberInRotateArray(self, rotateArray):
# write code here
if len(rotateArray) == 0:
return 0
min_b = rotateArray[0]
for i in range(len(rotateArray)):
if rotateArray[i] < min_b:
min_b = rotateArray[i]
return min_b
这题目鬼使一样,这么多要求就只喊打印最小值
剑指offer习题6
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转载自blog.csdn.net/u012693077/article/details/80788002
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