C语言-幸运值测试程序

#include <stdio.h>

//#include <conio.h> //consoleinput/output kbhit()\getch()

#include <Windows.h>

int count = 0;   //不停变换的数字

int    running= 1;//是否正在运行

int start = 0;     //是否开始

//多线程处理函数

DWORD WINAPI MyProc(LPVOID lpParam)

{

         while(running)

         {

                   if(start)

                   {

                            printf("%d",count = (count + 1) % 10);//让count的值保持在0-9之间

                            printf("\b");//让光标退一格http://www.jiakang021.com

                   }

                   Sleep(50);

         }

         return0;

}

int main()

{

         inti = 0;

         intaNum[4];    //保存4个幸运数字 

         intiluck;            //幸运值

         intadd, mul;    //加,乘

        

         HANDLEhThread;

         hThread= CreateThread(NULL, 0, MyProc, NULL, 0, NULL);

         CloseHandle(hThread);

        

         printf("---------测试你今天的幸运值-----------\n");

         printf("请按空格键开始和停止:\n");

        

         while(i< 4)

         {

                   if(kbhit()&& getch() == ' ')//如果我们按下了键并且该键是空格键 //逻辑运算符&& 且  ||或

                   {

                            start= !start;//取非运算符!原来的值为真,让它变成假,原来是假,让它变成真

                            if(start)

                            {

                                     printf("[%d->",i + 1);

                            }

                            else

                            {

                                     printf("%d]",count);

                                     aNum[i++]= count; //保存该幸运数字到数组当中

                            }

                   }                

         }

        

         running= 0;      //让子线程退出释放

        

         printf("\n你的幸运数字是:");

         //计算运气值

         add= mul = 0;

         for(i= 0; i < 4; i++)

         {

                   printf("%d",aNum[i]);

                   add+= aNum[i];                          //累加数组中的数字

         }

         printf("\n");

        

         mul= add;

         while(add>= 10)

         {

                   add= add / 10 + add % 10;//add = 45  ---> add = 9

         }

         while(mul>= 10)

         {

                   mul= add / 10 * (add % 10);//add = 45 ---> add = 20-----> add = 0

         }

         printf(",你的运气值为:%d\n",add * 10 + mul);

         getch();//让程序停留在此

        

         return0;

}

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转载自blog.csdn.net/moyouyou123/article/details/80852913