JS 获取显示屏参数

<html>

<body >
<input type="button" style="width:120px;" value="获取像素" onclick="getparam();"/>
<script language=JavaScript type=text/javascript>
function getparam(){

document.write("屏幕分辨率为:"+screen.width+"*"+screen.height+
"屏幕可用大小:"+screen.availWidth+"*"+screen.availHeight+
"网页可见区域宽:"+document.body.clientWidth+
"网页可见区域高:"+document.body.clientHeight+
"网页可见区域宽(包括边线的宽):"+document.body.offsetWidth+
"网页可见区域高(包括边线的宽):"+document.body.offsetHeight+
"网页正文全文宽:"+document.body.scrollWidth+
"网页正文全文高:"+document.body.scrollHeight+
"网页被卷去的高:"+document.body.scrollTop+
"网页被卷去的左:"+document.body.scrollLeft+
"网页正文部分上:"+window.screenTop+
"网页正文部分左:"+window.screenLeft+
"屏幕分辨率的高:"+window.screen.height+
"屏幕分辨率的宽:"+window.screen.width+
"屏幕可用工作区高度:"+window.screen.availHeight+
"屏幕可用工作区宽度:"+window.screen.availWidth
);

}
</script>
</body>
</html>

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转载自blog.csdn.net/wangzhen_csdn/article/details/80622144
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