js 获取url 参数

    function getUrlArg(url,key){
        var arr = url.split('?');
        var argStr = arr.length >1 ? arr[1]:"";
        if(!argStr){
            return "";
        }
        var arr2 = argStr.split('&').map(item=>item.split('='));
        var res = arr2.find(item=>item[0] == key);
        if(res){
            return res.length > 1 ? res[1] :"";
        }else{
            return "";
        }
    }
    var url = "https://www.xxx.com/s?name=zhang&age=12&aa";
    console.log(getUrlArg(url,"name"));
    console.log(getUrlArg(url,"age"));
    console.log(getUrlArg(url,"sex"));

猜你喜欢

转载自www.cnblogs.com/jlyuan/p/12031802.html
今日推荐