斐波那契数列C++

#include<iostream>
#include<stdio.h>
#include<stdlib.h>

using namespace std;


int main(){
	int n,sum=0;
	int num[] = {0,1};
	cin >> n; 
	for(int i=2;i<=(n+2);i++){
		num[i] = num[i-2]+num[i-1];
	}
	for(int i=0;i<=(n+2);i++){
		cout<< num[i] <<" ";
		sum+=num[i];
	}
	cout<< endl<< sum <<endl;
	return 0;
}