BZOJ 4800 [Ceoi2015]Ice Hockey World Championship

题目中文,不解释,(这个ceoi貌似是欧洲的emm)

一眼背包,两眼看到longlong的数据,三眼果断弃掉dp

正解为折半暴搜,先搜前n/2小,再搜后n/2

然后一边暴搜后n/2,一边统计方案数

思路讲不清emmmmm,日后更新

#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
long long int m,cost[50];
int n,mid,lim,cnt=0;
long long int ans[2000000],que=0;
int dfs1(int x,long long int sum)
{
    if (sum>m) return 0;
    if (x==lim+1)
    {
        ans[++cnt]=sum;
        return 0;
    }
    dfs1(x+1,sum);
    dfs1(x+1,sum+cost[x]);
    return 0;
}
int dfs2(int x,long long int sum)
{
    if (sum>m) return 0;
    if (x==lim+1)
    {
        if (ans[1]+sum>m) return 0;
        int l=1,r=cnt;int md=(l+r)/2,tot=0;
        while (l<=r)
        {
            md=(l+r)/2;
            if (sum+ans[md]<=m) tot=md,l=md+1;
            else r=md-1;
        }
        que+=tot;
        return 0;
    }
    dfs2(x+1,sum+cost[x]);
    dfs2(x+1,sum);
    return 0;
}
int main()
{
    cin>>n>>m;
    for (int i=1;i<=n;i++) cin>>cost[i];
    lim=mid=n/2;
    dfs1(1,0);
    sort(ans+1,ans+cnt+1);
    lim=n;
    dfs2(mid+1,0);
    cout<<que;
    return 0;
}

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转载自blog.csdn.net/acerandaker/article/details/79954060