图的BFS

问题

分别用邻接矩阵和邻接表实现图的BFS算法

邻接矩阵

//邻接矩阵版
int n,G[maxn][maxn];
bool vis[maxn] = {
    
    false};

void BFS(int u){
    
    
    queue<int> q;
    q.push(u);
    inq[u] = true;
    while (!q.empty()){
    
    
        int u = q.front();
        q.pop();
        for (int v = 0; v < n; ++v) {
    
    
            if(inq[v] == false && G[u][v]!=INF){
    
    
                q.push(v);
                inq[v] = true;
            }
        }
    }
}
void BFSTrave(){
    
    
    for (int u = 0; u < n; ++u) {
    
    
        if(inq[u] == false){
    
    
            BFS(u);
        }
    }
}

邻接表

//邻接表版本
vector<int> Adj[maxn];
void BFS1(int u){
    
    
    queue<int> q;
    q.push(u);
    inq[u] = true;
    while (!q.empty()){
    
    
        int u = q.front();
        q.pop();
        for (int i = 0; i < Adj[u].size(); ++i) {
    
    
            int v = Adj[u][i];
            if(inq[v] == false){
    
    
                q.push(v);
                inq[v] = true;
            }
        }
    }
}
void BFSTrave1(){
    
    
    for (int u = 0; u < n; ++u) {
    
    
        if(inq[u]== false){
    
    
            BFS1(u);
        }
    }
}

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转载自blog.csdn.net/qq_19272233/article/details/119965697