Piggy-Bank HDU - 1114 (完全背包)

P - Piggy-Bank

 题目连接:HDU - 1114

题意:存钱罐中存了好多硬币,已知空存钱罐的重量和装满钱的存钱罐重量,以及n种硬币的价值和重量,求出存钱罐中至少存了多少钱;

每种硬币的数量是无穷的,所以是个完全背包问题,求至少存了多少钱,是求最小值问题,和以往的最大值问题有所不同,初始化dp[i]为无穷大,dp[0]=0;状态转移方程为dp[i]=min(dp[i], dp[i-w[i]]+p[i]);

#include <bits/stdc++.h>
using namespace std;
const int maxn=10100;
const int INF=0x3f3f3f3f;
int E, F, n;
int dp[maxn];
int p[510], w[510];
int main(){
    int T;
    scanf("%d", &T);
    while(T--){
        scanf("%d%d", &E, &F);
        int V=F-E;
        scanf("%d", &n);
        for(int i=0; i<n; i++){
            scanf("%d%d", &p[i], &w[i]);
        }
        memset(dp, INF, sizeof(dp));
        dp[0]=0;
        for(int i=0; i<n; i++){
            for(int j=w[i]; j<=V; j++){
                dp[j]=min(dp[j], dp[j-w[i]]+p[i]);
            }
        }
        if(dp[V]>=INF) printf("This is impossible.\n");
        else printf("The minimum amount of money in the piggy-bank is %d.\n", dp[V]);
    }
    return 0;
}

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转载自blog.csdn.net/sirius_han/article/details/80598732