LeetCode——字符串转数字

public int myAtoi(String str) {

        long ans = 0;
        boolean flag = false;
        // 先去掉前后空格
        str = str.trim();
        int pos = 0;
        if (pos < str.length() && str.charAt(pos) == '+') {
            pos++;
        } else {
            if (pos < str.length() && str.charAt(pos) == '-') {
                flag = true;
                pos++;
            }
        }

        for (int i = pos; i < str.length(); i++) {
            char c = str.charAt(i);
            if (Character.isDigit(c)) {
                int digit = Character.digit(c, 10);
                ans = ans * 10 + digit;
            } else {
                break;
            }
        }

        // 环境只能存储 32 位有符号整数,其数值范围是 [−2^31,  2^31 − 1]
        if (flag) {
            if (-ans < Integer.MIN_VALUE) {
                ans = Integer.MIN_VALUE;
                return (int) ans;
            }
            return (int) -ans;
        } else {
            if (ans > Integer.MAX_VALUE) {
                ans = Integer.MAX_VALUE;
                return (int) ans;
            }
        }
        return (int) ans;
    }

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转载自blog.csdn.net/reuxfhc/article/details/80195092