描述
Given an array of integers nums.
A pair (i,j) is called good if nums[i] == nums[j] and i < j.
Return the number of good pairs.
Example 1:
Input: nums = [1,2,3,1,1,3]
Output: 4
Explanation: There are 4 good pairs (0,3), (0,4), (3,4), (2,5) 0-indexed.
Example 2:
Input: nums = [1,1,1,1]
Output: 6
Explanation: Each pair in the array are good.
Example 3:
Input: nums = [1,2,3]
Output: 0
Note:
1 <= nums.length <= 100
1 <= nums[i] <= 100
解析
根据题意,只需要用字典结构统计出现的字符和对应的出现次数,然后遍历字典,将大于等于 2 的字符的出现次数,都按照公式 n*(n-1)/2 ,计算该字母能形成合法的 (i,j) 组合的次数,最后求和即可得到答案。如果编程经验丰富一行代码即可解决。
解答
class Solution(object):
def numIdenticalPairs(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
res = 0
for v in collections.Counter(nums).values():
if v>1:
res += v*(v-1)/2
return res
运行结果
Runtime: 12 ms, faster than 98.96% of Python online submissions for Number of Good Pairs.
Memory Usage: 13.4 MB, less than 73.07% of Python online submissions for Number of Good Pairs.
原题链接:https://leetcode.com/problems/number-of-good-pairs/
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