LeetCode - Easy - 326. Power of Three

Topic

  • Math

Description

https://leetcode.com/problems/power-of-three/

Given an integer n, return true if it is a power of three. Otherwise, return false.

An integer n is a power of three, if there exists an integer x such that n == 3x.

Example 1:

Input: n = 27
Output: true

Example 2:

Input: n = 0
Output: false

Example 3:

Input: n = 9
Output: true

Example 4:

Input: n = 45
Output: false

Constraints:

  • -2³¹ <= n <= 2³¹ - 1

Analysis

Submission

public class PowerOfThree {
    
    

	//方法一:switch版
	public boolean isPowerOfThree1(int num) {
    
    
		switch (num) {
    
    
			case 1: return true;
			case 3: return true;
			case 9: return true;
			case 27: return true;
			case 81: return true;
			case 243: return true;
			case 729: return true;
			case 2187: return true;
			case 6561: return true;
			case 19683: return true;
			case 59049: return true;
			case 177147: return true;
			case 531441: return true;
			case 1594323: return true;
			case 4782969: return true;
			case 14348907: return true;
			case 43046721: return true;
			case 129140163: return true;
			case 387420489: return true;
			case 1162261467: return true;
			default: return false;
		}
	}
	
	//方法二:求余
	public boolean isPowerOfThree2(int n) {
    
    
		// 1162261467 is 3^19, 3^20 is bigger than int
		return n > 0 && 1162261467 % n == 0;
	}

	//方法三:递归
	public boolean isPowerOfThree3(int n) {
    
    
		return n > 0 && (n == 1 || (n % 3 == 0 && isPowerOfThree3(n / 3)));
	}

	//方法四:迭代
	public boolean isPowerOfThree4(int n) {
    
    
		if (n > 1)
			while (n % 3 == 0)
				n /= 3;
		return n == 1;
	}

	
	private static HashSet<Integer> POWER_OF_THREE_SET = new HashSet<>(
			Arrays.asList(1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323, 4782969,
					14348907, 43046721, 129140163, 387420489, 1162261467));

	//方法五:哈希表缓存
	public boolean isPowerOfThree5(int n) {
    
    
		return POWER_OF_THREE_SET.contains(n);
	}

	private static int[] POWER_OF_THREE_LIST = new int[] {
    
     1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147,
			531441, 1594323, 4782969, 14348907, 43046721, 129140163, 387420489, 1162261467 };

	//方法六:二分查找缓存
	public boolean isPowerOfThree6(int n) {
    
    
		return Arrays.binarySearch(POWER_OF_THREE_LIST, n) >= 0;
	}

}


Test

import static org.junit.Assert.*;

import java.util.ArrayList;
import java.util.List;


import org.junit.Test;

public class PowerOfThreeTest {
    
    

	public static List<Integer> POWER_OF_THREE_LIST;
	
	static {
    
    
		List<Integer> result = new ArrayList<Integer>();
		for(int i = 0; ; i++) {
    
    
			int product = 1, lastPrduct = 0;
			
			for(int j = 1; j <= i; j++) {
    
    
				lastPrduct = product;
				product *= 3;
			}
			
			if(product / 3 != lastPrduct)
				break;
			
			//System.out.println(product + " : " + Integer.toBinaryString(product));
			//System.out.println("case " + product + ": return true;");
			result.add(product);
		}
		
		POWER_OF_THREE_LIST = result;
	}
	
	@Test
	public void test() {
    
    
		PowerOfThree obj = new PowerOfThree();

		for(int num : POWER_OF_THREE_LIST) {
    
    
			assertTrue(obj.isPowerOfThree1(num));
			assertTrue(obj.isPowerOfThree2(num));
			assertTrue(obj.isPowerOfThree3(num));
			assertTrue(obj.isPowerOfThree4(num));
			assertTrue(obj.isPowerOfThree5(num));
			assertTrue(obj.isPowerOfThree6(num));
		}
		
	}
	
}

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转载自blog.csdn.net/u011863024/article/details/113158559