PAT甲级-字符串处理类型-1082 Read Number in Chinese解题思路

1082 Read Number in Chinese (25 分)

思路

这道字符串算是比较难了，恰烂分代码12分

#include <bits/stdc++.h>
using namespace std;

int main()
{
    
    
    char name[10][10]={
    
    "ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    string str;
    cin>>str;

    int len = str.length();
    int len2 =len;
    int start = 0;
    if(str[0]=='-')
    {
    
    
        cout<<"Fu ";
        start +=1 ;
        len2-=1;
    }    

    if(len2>8)
        printf("%s Yi %s Qian %s Bai %s Shi %s Wan %s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48],name[int(str[start+4])-48],name[int(str[start+5])-48],name[int(str[start+6])-48],name[int(str[start+7])-48],name[int(str[start+8])-48]);
    else if(len2==8)
        printf("%s Qian %s Bai %s Shi %s Wan %s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48],name[int(str[start+4])-48],name[int(str[start+5])-48],name[int(str[start+6])-48],name[int(str[start+7])-48]);
    else if(len2==7)
        printf("%s Bai %s Shi %s Wan %s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48],name[int(str[start+4])-48],name[int(str[start+5])-48],name[int(str[start+6])-48]);
    else if(len2==6)
        printf("%s Shi %s Wan %s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48],name[int(str[start+4])-48],name[int(str[start+5])-48]);
    else if(len2==5)
        printf("%s Wan %s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48],name[int(str[start+4])-48]);
    else if(len2==4)
        printf("%s Qian %s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48],name[int(str[start+3])-48]);
    else if(len2==3)
        printf("%s Bai %s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48],name[int(str[start+2])-48]);
    else if(len2==2)
        printf("%s Shi %s",name[int(str[start])-48],name[int(str[start+1])-48]);
    else if(len2==1)
        printf("%s",name[int(str[start])-48]);  
}

参考算法笔记，分组进行精细的讨论。
代码虽然满分，但是有个bug，开头为0的数字没有考虑，这种输入输出明显不合理。但好像也不必考虑，只考虑为0的情况即可。
001
ling Bai ling yi

代码

#include <bits/stdc++.h>
using namespace std;

int main()
{
    
    
    char name[10][10]={
    
    "ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    char wei[5][5] = {
    
    "Shi","Bai","Qian","Wan","Yi"};
    string str;
    cin>>str;

    int len = str.length();
    int right =len-1;
    int left = 0;
    if(str[0]=='-')
    {
    
    
        cout<<"Fu";
        left +=1 ;
    }    

    while(left+4 <= right)
        right -=4;

    while(left <len)
    {
    
    
        bool flag =false;
        bool print = false;
        while(left<=right)
        {
    
    
            if(left>0 && str[left]=='0') //很神奇，left>0没有就出错
                flag = true;
            else
            {
    
    
                if(flag == true)
                {
    
    
                    printf(" ling");
                    flag = false;
                } 
                if(left>0) printf(" ");
                printf("%s",name[str[left]-48]); 
                print = true;
                if(left != right)
                    printf(" %s",wei[right-left-1]);
            }
            left ++;
        }
        if(print == true && right!=len-1)
            printf(" %s",wei[(len-right-1)/4 + 2]);
        right +=4;
    }
}