C/C++编程学习 - 第21周 ⑨ 求和

题目链接

题目描述

编程实现输入两个整数a,b，
当a+b=1时输出one，
a+b=2时输出two,
a+b=3时输出three,
a+b=4时输出four,
a+b=5时输出five,
a+b=6时输出six,
a+b=7时输出seven,
a+b=8时输出eight,
a+b=9时输出nine,否则输出None（提示：switch语句）

Input
输入两个整数a,b，以空格隔开
Output
输出相应单词

Sample Input

3 5

Sample Output

eight

思路

根据题目进行操作，写switch语句或是if-else语句都行。

C++代码：

#include<bits/stdc++.h>
using namespace std;
int main()
{
    
    
	int a, b;
	while(cin >> a >> b)
	{
    
    
		if(a + b == 1) cout << "one" << endl;
		else if(a + b == 2) cout << "two" << endl;
		else if(a + b == 3) cout << "three" << endl;
		else if(a + b == 4) cout << "four" << endl;
		else if(a + b == 5) cout << "five" << endl;
		else if(a + b == 6) cout << "six" << endl;
		else if(a + b == 7) cout << "seven" << endl;
		else if(a + b == 8) cout << "eight" << endl;
		else if(a + b == 9) cout << "nine" << endl;
		else cout << "None" << endl;
	}
	return 0;
}