扫雷游戏初级版(C语言)

主要思路:

  1. 先开始设置两个数组,一个放置雷的信息,一个是玩家玩游戏时显示的棋盘
  2. 对两个数组进行初始化
  3. 布置雷的信息,将雷的信息布置在第一个数组中
  4. 打印棋盘,此时只需要打印玩家玩游戏的棋盘就可以
  5. 在打印出来的棋盘输入坐标信息扫雷,输入的坐标周围有雷的话,会显示相应的数字

1 主函数

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"

void menu()
{
    
    
	printf("************************\n");
	printf("*****1.paly  0.exit*****\n");
	printf("************************\n");
}

void game()
{
    
    
	//雷的信息存储
	//1.布置好的雷的信息
	char mine[ROWS][COLS] = {
    
    0};
	//2.排查出的雷的信息
	char show[ROWS][COLS] = {
    
    0};
	//初始化
	InitBoard(mine, ROWS, COLS, '0');
	InitBoard(show, ROWS, COLS, '*');
	
	//布置雷
	SetMine(mine, ROW, COL);
	//打印棋盘
	//DisplayBoard(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);

	//DisplayBoard(mine, ROW, COL);
	//扫雷
	FindMine(mine, show, ROW, COL);
}

void test()
{
    
    
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
    
    
		menu();
		printf("请选择:>");
		scanf("%d", &input);
		switch (input)
		{
    
    
		case 1:
			game();
			break;
		case 0:
				printf("退出游戏\n");
				break;
		default:
			printf("选择错误,请重新选择!\n");
			break;
		}
	} while (input);
}

int main()
{
    
    
	test();
	return 0;
}

2 游戏的声明

#include <stdlib.h>
#include <time.h>
#include <stdio.h>

#define ROW 9
#define COL 9

#define EASY_COUNT 10

#define ROWS ROW+2
#define COLS COL+2

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

3游戏的主体

#include "game.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
    
    
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
    
    
		for (j = 0; j < cols; j++)
		{
    
    
			board[i][j] = set;
		}
	}
}

void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
    
    
	int i = 0;
	int j = 0;
	//打印列号
	for (i = 0; i <= col; i++)
	{
    
    
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)
	{
    
    
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
    
    
			printf("%c ", board[i][j]);
		}
		printf("\n");
	}
}

void SetMine(char board[ROWS][COLS], int row, int col)
{
    
    
	int count = EASY_COUNT;
	while (count)
	{
    
    
		int x = rand() % row + 1;
		int y = rand() % col + 1;
		if (board[x][y] == '0')
		{
    
    
			board[x][y] = '1';
			count--;
		}
	}
}

//'0' - '0' = 0
//'1' - '0' = 1
//'3' - '0' = 3

int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
    
    
	return mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y-1] +
	mine[x + 1][y]+ mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1] - 8*'0';
}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
    
    
	int x = 0;
	int y = 0;
	int win = 0;
	while (win<row*col - EASY_COUNT)
	{
    
    
		printf("输入坐标:>");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
    
    
			//坐标合法
			//1.踩雷
			if (mine[x][y] == '1')
			{
    
    
				printf("踩雷\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else//不是雷
			{
    
    
				//计算x,y坐标周围有几个雷
				int count = get_mine_count(mine, x, y);
				show[x][y] = count + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else
		{
    
    
			printf("输入非法,重新输入!\n");
		}
	}
	if (win == row*col - EASY_COUNT)
	{
    
    
		printf("成功\n");
		DisplayBoard(mine, row, col);
	}
}

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转载自blog.csdn.net/aaaaauaan/article/details/105080527