字典树-HDU1251(模板)

题目大意:

给n个匹配串.然后给m个模式串,查询它们作为前缀在匹配串中出现的次数.

思路: Trie树

#include<bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 5;
namespace Trie{
    
    
    int tr[maxn][27] , v[maxn] , tot;
    void init ()
    {
    
    
        tot = 0;
        for(int i = 0 ; i < maxn ; i++) {
    
    
            for(int j = 0 ; j < 26 ; j++) tr[i][j] = 0;
            v[i] = 0;
        }
    }
    void add (char * s){
    
    
        int u = 0;v[u]++;
        for (int i = 1 ; s[i] ; i++){
    
    
            if (!tr[u][s[i] - 'a']) tr[u][s[i] - 'a'] = ++tot;
            u = tr[u][s[i] - 'a'];
            v[u]++;
        }
    }
    int ask (char * s){
    
    
        int u = 0;
        for(int i = 1 ; s[i] ; i++){
    
    
            if (!tr[u][s[i] - 'a']) return 0;
            u = tr[u][s[i] - 'a'];
        }
        return v[u];
    }
}
char tmp[15];
int main()
{
    
    
    ios::sync_with_stdio(false);
    while (1){
    
    
        cin.getline(tmp + 1, 11);
        if (strlen(tmp + 1) == 0) break;
        Trie::add(tmp);
    }
    while(cin >> (tmp + 1)){
    
    
        cout << Trie::ask(tmp) << endl;
    }
    return 0;
}

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转载自blog.csdn.net/qq_35577488/article/details/109073519