复习:在前面我们已经学习了Pandas基础,第二章我们开始进入数据分析的业务部分,在第二章第一节的内容中,我们学习了 数据的清洗 ,这一部分十分重要,只有数据变得相对干净,我们之后对数据的分析才可以更有力。而这一节,我们要做的是数据重构,数据重构依旧属于数据理解(准备)的范围。
开始之前,导入numpy、pandas包和数据
import numpy as np
import pandas as pd
text = pd. read_csv( './data/train-left-up.csv' )
text. head( )
PassengerId
Survived
Pclass
Name
0
1
0
3
Braund, Mr. Owen Harris
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
2
3
1
3
Heikkinen, Miss. Laina
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
4
5
0
3
Allen, Mr. William Henry
2 第二章:数据重构
2.4 数据的合并
2.4.1 任务一:将data文件夹里面的所有数据都载入,观察数据的之间的关系
text_left_up = pd. read_csv( "data/train-left-up.csv" )
text_left_down = pd. read_csv( "data/train-left-down.csv" )
text_right_up = pd. read_csv( "data/train-right-up.csv" )
text_right_down = pd. read_csv( "data/train-right-down.csv" )
display( text_left_up. tail( ) )
display( text_left_down. head( ) )
PassengerId
Survived
Pclass
Name
434
435
0
1
Silvey, Mr. William Baird
435
436
1
1
Carter, Miss. Lucile Polk
436
437
0
3
Ford, Miss. Doolina Margaret "Daisy"
437
438
1
2
Richards, Mrs. Sidney (Emily Hocking)
438
439
0
1
Fortune, Mr. Mark
PassengerId
Survived
Pclass
Name
0
440
0
2
Kvillner, Mr. Johan Henrik Johannesson
1
441
1
2
Hart, Mrs. Benjamin (Esther Ada Bloomfield)
2
442
0
3
Hampe, Mr. Leon
3
443
0
3
Petterson, Mr. Johan Emil
4
444
1
2
Reynaldo, Ms. Encarnacion
display( text_right_up. tail( ) )
display( text_right_down. head( ) )
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
886
male
27.0
0.0
0.0
211536
13.00
NaN
S
887
female
19.0
0.0
0.0
112053
30.00
B42
S
888
female
NaN
1.0
2.0
W./C. 6607
23.45
NaN
S
889
male
26.0
0.0
0.0
111369
30.00
C148
C
890
male
32.0
0.0
0.0
370376
7.75
NaN
Q
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
male
31.0
0
0
C.A. 18723
10.500
NaN
S
1
female
45.0
1
1
F.C.C. 13529
26.250
NaN
S
2
male
20.0
0
0
345769
9.500
NaN
S
3
male
25.0
1
0
347076
7.775
NaN
S
4
female
28.0
0
0
230434
13.000
NaN
S
【提示】结合之前我们加载的train.csv数据,大致预测一下上面的数据是什么
2.4.2:任务二:使用concat方法:将数据train-left-up.csv和train-right-up.csv横向合并为一张表,并保存这张表为result_up
result_up= pd. concat( [ text_left_up, text_right_up. loc[ : 438 ] ] , axis= 1 )
result_up
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
...
...
...
...
...
...
...
...
...
...
...
...
...
434
435
0
1
Silvey, Mr. William Baird
male
50.0
1.0
0.0
13507
55.9000
E44
S
435
436
1
1
Carter, Miss. Lucile Polk
female
14.0
1.0
2.0
113760
120.0000
B96 B98
S
436
437
0
3
Ford, Miss. Doolina Margaret "Daisy"
female
21.0
2.0
2.0
W./C. 6608
34.3750
NaN
S
437
438
1
2
Richards, Mrs. Sidney (Emily Hocking)
female
24.0
2.0
3.0
29106
18.7500
NaN
S
438
439
0
1
Fortune, Mr. Mark
male
64.0
1.0
4.0
19950
263.0000
C23 C25 C27
S
439 rows × 12 columns
2.4.3 任务三:使用concat方法:将train-left-down和train-right-down横向合并为一张表,并保存这张表为result_down。然后将上边的result_up和result_down纵向合并为result。
result_down= pd. concat( [ text_left_down, text_right_down] , axis= 1 )
result_down
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
440
0
2
Kvillner, Mr. Johan Henrik Johannesson
male
31.0
0
0
C.A. 18723
10.500
NaN
S
1
441
1
2
Hart, Mrs. Benjamin (Esther Ada Bloomfield)
female
45.0
1
1
F.C.C. 13529
26.250
NaN
S
2
442
0
3
Hampe, Mr. Leon
male
20.0
0
0
345769
9.500
NaN
S
3
443
0
3
Petterson, Mr. Johan Emil
male
25.0
1
0
347076
7.775
NaN
S
4
444
1
2
Reynaldo, Ms. Encarnacion
female
28.0
0
0
230434
13.000
NaN
S
...
...
...
...
...
...
...
...
...
...
...
...
...
447
887
0
2
Montvila, Rev. Juozas
male
27.0
0
0
211536
13.000
NaN
S
448
888
1
1
Graham, Miss. Margaret Edith
female
19.0
0
0
112053
30.000
B42
S
449
889
0
3
Johnston, Miss. Catherine Helen "Carrie"
female
NaN
1
2
W./C. 6607
23.450
NaN
S
450
890
1
1
Behr, Mr. Karl Howell
male
26.0
0
0
111369
30.000
C148
C
451
891
0
3
Dooley, Mr. Patrick
male
32.0
0
0
370376
7.750
NaN
Q
452 rows × 12 columns
2.4.4 任务四:使用DataFrame自带的方法join方法和append:完成任务二和任务三的任务
result_up= text_left_up. join( text_right_up)
result_down= text_left_down. join( text_right_down)
result= result_up. append( result_down)
result
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
...
...
...
...
...
...
...
...
...
...
...
...
...
447
887
0
2
Montvila, Rev. Juozas
male
27.0
0.0
0.0
211536
13.0000
NaN
S
448
888
1
1
Graham, Miss. Margaret Edith
female
19.0
0.0
0.0
112053
30.0000
B42
S
449
889
0
3
Johnston, Miss. Catherine Helen "Carrie"
female
NaN
1.0
2.0
W./C. 6607
23.4500
NaN
S
450
890
1
1
Behr, Mr. Karl Howell
male
26.0
0.0
0.0
111369
30.0000
C148
C
451
891
0
3
Dooley, Mr. Patrick
male
32.0
0.0
0.0
370376
7.7500
NaN
Q
891 rows × 12 columns
2.4.5 任务五:使用Panads的merge方法和DataFrame的append方法:完成任务二和任务三的任务
result_up= pd. merge( text_left_up, text_right_up, left_index= True , right_index= True )
result_down= pd. merge( text_left_down, text_right_down, left_index= True , right_index= True )
result= result_up. append( result_down)
result
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
...
...
...
...
...
...
...
...
...
...
...
...
...
447
887
0
2
Montvila, Rev. Juozas
male
27.0
0.0
0.0
211536
13.0000
NaN
S
448
888
1
1
Graham, Miss. Margaret Edith
female
19.0
0.0
0.0
112053
30.0000
B42
S
449
889
0
3
Johnston, Miss. Catherine Helen "Carrie"
female
NaN
1.0
2.0
W./C. 6607
23.4500
NaN
S
450
890
1
1
Behr, Mr. Karl Howell
male
26.0
0.0
0.0
111369
30.0000
C148
C
451
891
0
3
Dooley, Mr. Patrick
male
32.0
0.0
0.0
370376
7.7500
NaN
Q
891 rows × 12 columns
利用merge来做纵列的合并
result_left= pd. merge( text_left_up, text_left_down, how= 'outer' )
text_right_up[ 'key' ] = 0
text_right_down[ 'key' ] = 1
text_right_up
text_right_down
result_right= pd. merge( text_right_up. loc[ : 438 ] , text_right_down, how= 'outer' )
result= pd. merge( result_left, result_right. iloc[ : , : - 1 ] , left_index= True , right_index= True )
result
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
...
...
...
...
...
...
...
...
...
...
...
...
...
886
887
0
2
Montvila, Rev. Juozas
male
27.0
0.0
0.0
211536
13.0000
NaN
S
887
888
1
1
Graham, Miss. Margaret Edith
female
19.0
0.0
0.0
112053
30.0000
B42
S
888
889
0
3
Johnston, Miss. Catherine Helen "Carrie"
female
NaN
1.0
2.0
W./C. 6607
23.4500
NaN
S
889
890
1
1
Behr, Mr. Karl Howell
male
26.0
0.0
0.0
111369
30.0000
C148
C
890
891
0
3
Dooley, Mr. Patrick
male
32.0
0.0
0.0
370376
7.7500
NaN
Q
891 rows × 12 columns
【思考】对比merge、join以及concat的方法的不同以及相同。思考一下在任务四和任务五的情况下,为什么都要求使用DataFrame的append方法,如何只要求使用merge或者join可不可以完成任务四和任务五呢?
append像序列中添加行
assign 更像是左连接,一列一列的像序列中添加列
combine 求两个表的并集
update 把一个表里面的元素参照另一个表进行更新
concat 可以将两个表在两个维度进行拼接
merge 通过指定一个key来将两个表进行连接
join 也可以指定key,默认的话就是按照index来进行连接
2.4.6 任务六:完成的数据保存为result.csv
result. to_csv( 'result.csv' )
2.5 换一种角度看数据
2.5.1 任务一:将我们的数据变为Series类型的数据
stack函数可以看做将横向的索引放到纵向,因此功能类似与melt,参数level可指定变化的列索引是哪一层(或哪几层,需要列表)
text = pd. read_csv( 'result.csv' )
text. head( )
Unnamed: 0
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
unit_result= text. stack( ) . head( 20 )
unit_result
0 Unnamed: 0 0
PassengerId 1
Survived 0
Pclass 3
Name Braund, Mr. Owen Harris
Sex male
Age 22
SibSp 1
Parch 0
Ticket A/5 21171
Fare 7.25
Embarked S
1 Unnamed: 0 1
PassengerId 2
Survived 1
Pclass 1
Name Cumings, Mrs. John Bradley (Florence Briggs Th...
Sex female
Age 38
SibSp 1
dtype: object
unit_result. unstack( )
Unnamed: 0
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Embarked
0
0
1
0
3
Braund, Mr. Owen Harris
male
22
1
0
A/5 21171
7.25
S
1
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38
1
NaN
NaN
NaN
NaN
unit_result. to_csv( 'unit_result.csv' )
test = pd. read_csv( 'unit_result.csv' )
test. head( )
Unnamed: 0
Unnamed: 1
0
0
0
Unnamed: 0
0
1
0
PassengerId
1
2
0
Survived
0
3
0
Pclass
3
4
0
Name
Braund, Mr. Owen Harris
test. iloc[ : , 1 : ]
Unnamed: 1
0
0
Unnamed: 0
0
1
PassengerId
1
2
Survived
0
3
Pclass
3
4
Name
Braund, Mr. Owen Harris
5
Sex
male
6
Age
22.0
7
SibSp
1.0
8
Parch
0.0
9
Ticket
A/5 21171
10
Fare
7.25
11
Embarked
S
12
Unnamed: 0
1
13
PassengerId
2
14
Survived
1
15
Pclass
1
16
Name
Cumings, Mrs. John Bradley (Florence Briggs Th...
17
Sex
female
18
Age
38.0
19
SibSp
1.0
test. info( )
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 20 entries, 0 to 19
Data columns (total 3 columns):
# Column Non-Null Count Dtype
--- ------ -------------- -----
0 Unnamed: 0 20 non-null int64
1 Unnamed: 1 20 non-null object
2 0 20 non-null object
dtypes: int64(1), object(2)
memory usage: 608.0+ bytes
复习:在前面我们已经学习了Pandas基础,第二章我们开始进入数据分析的业务部分,在第二章第一节的内容中,我们学习了 数据的清洗 ,这一部分十分重要,只有数据变得相对干净,我们之后对数据的分析才可以更有力。而这一节,我们要做的是数据重构,数据重构依旧属于数据理解(准备)的范围。
开始之前,导入numpy、pandas包和数据
import pandas as pd
import numpy as np
text = pd. read_csv( 'result.csv' )
text. head( )
Unnamed: 0
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
3
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
4
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
2 第二章:数据重构
第一部分:数据聚合与运算
2.6 数据运用
2.6.1 任务一:通过教材《Python for Data Analysis》P303、Google or anything来学习了解GroupBy机制
2.4.2:任务二:计算泰坦尼克号男性与女性的平均票价
text. groupby( 'Sex' ) [ 'Fare' ] . mean( )
Sex
female 44.479818
male 25.523893
Name: Fare, dtype: float64
在了解GroupBy机制之后,运用这个机制完成一系列的操作,来达到我们的目的。
下面通过几个任务来熟悉GroupBy机制。
2.4.3:任务三:统计泰坦尼克号中男女的存活人数
text. groupby( 'Sex' ) [ 'Survived' ] . sum ( )
Sex
female 233
male 109
Name: Survived, dtype: int64
text. groupby( 'Sex' ) [ 'Survived' ] . count( )
Sex
female 314
male 577
Name: Survived, dtype: int64
text. groupby( 'Sex' ) [ 'Survived' ] . sum ( ) / text. groupby( 'Sex' ) [ 'Survived' ] . count( )
Sex
female 0.742038
male 0.188908
Name: Survived, dtype: float64
2.4.4:任务四:计算客舱不同等级的存活人数
text. groupby( 'Pclass' ) [ 'Survived' ] . sum ( )
Pclass
1 136
2 87
3 119
Name: Survived, dtype: int64
text. groupby( 'Pclass' ) [ 'Survived' ] . count( )
Pclass
1 216
2 184
3 491
Name: Survived, dtype: int64
text. groupby( 'Pclass' ) [ 'Survived' ] . sum ( ) / text. groupby( 'Pclass' ) [ 'Survived' ] . count( )
Pclass
1 0.629630
2 0.472826
3 0.242363
Name: Survived, dtype: float64
统计不同等级客舱中男女比例
text. groupby( [ 'Pclass' , 'Sex' ] ) . head( 1 )
Unnamed: 0
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
0
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
1
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
2
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
6
6
7
0
1
McCarthy, Mr. Timothy J
male
54.0
0.0
0.0
17463
51.8625
E46
S
9
9
10
1
2
Nasser, Mrs. Nicholas (Adele Achem)
female
14.0
1.0
0.0
237736
30.0708
NaN
C
17
17
18
1
2
Williams, Mr. Charles Eugene
male
NaN
0.0
0.0
244373
13.0000
NaN
S
text. groupby( [ 'Pclass' , 'Sex' ] ) [ 'PassengerId' ] . count( ) / [ 94 + 76 + 144 , 122 + 108 + 347 , 94 + 76 + 144 , 122 + 108 + 347 , 94 + 76 + 144 , 122 + 108 + 347 ]
Pclass Sex
1 female 0.299363
male 0.211438
2 female 0.242038
male 0.187175
3 female 0.458599
male 0.601386
Name: PassengerId, dtype: float64
【提示: 】表中的存活那一栏,可以发现如果还活着记为1,死亡记为0
【思考 】从数据分析的角度,上面的统计结果可以得出那些结论
#思考心得 女性更倾向与买贵一些的票,同时女性的存活率显著的比男性高,对比不同仓位中男女所占的比例也可以看出,相比男性在女性的群体中 更倾向于住好一些的客舱,这可能也就是存活率高的原因。
【思考】从任务二到任务四中,这些运算可以通过agg()函数来同时计算。并且可以使用rename函数修改列名。你可以按照提示写出这个过程吗?
text. groupby( 'Sex' ) . agg( { 'Fare' : [ ( 'rename_mean' , 'mean' ) ] , 'Survived' : [ ( 'rename_sum' , 'sum' ) ] } )
Fare
Survived
rename_mean
rename_sum
Sex
female
44.479818
233
male
25.523893
109
text. groupby( 'Pclass' ) . agg( { 'Survived' : [ 'sum' ] } ) . rename( columns= { 'sum' : 'rename_sum' } )
Survived
rename_sum
Pclass
1
136
2
87
3
119
2.4.5:任务五:统计在不同等级的票中的不同年龄的船票花费的平均值
text. groupby( [ 'Pclass' , 'Age' ] ) [ 'Fare' ] . mean( )
Pclass Age
1 0.92 151.5500
2.00 151.5500
4.00 81.8583
11.00 120.0000
14.00 120.0000
...
3 61.00 6.2375
63.00 9.5875
65.00 7.7500
70.50 7.7500
74.00 7.7750
Name: Fare, Length: 182, dtype: float64
text[ 'P_A_Fare_mean' ] = text[ 'Fare' ]
for name , group in text. groupby( [ 'Pclass' , 'Age' ] ) :
text. loc[ group. index, 'P_A_Fare_mean' ] = pd. Series( group[ 'Fare' ] . mean( ) , index= group. index, name= 'P_A_Fare_mean' )
text. head( )
Unnamed: 0
PassengerId
Survived
Pclass
Name
Sex
Age
SibSp
Parch
Ticket
Fare
Cabin
Embarked
P_A_Fare_mean
0
0
1
0
3
Braund, Mr. Owen Harris
male
22.0
1.0
0.0
A/5 21171
7.2500
NaN
S
7.988330
1
1
2
1
1
Cumings, Mrs. John Bradley (Florence Briggs Th...
female
38.0
1.0
0.0
PC 17599
71.2833
C85
C
103.711800
2
2
3
1
3
Heikkinen, Miss. Laina
female
26.0
0.0
0.0
STON/O2. 3101282
7.9250
NaN
S
14.158036
3
3
4
1
1
Futrelle, Mrs. Jacques Heath (Lily May Peel)
female
35.0
1.0
0.0
113803
53.1000
C123
S
165.744911
4
4
5
0
3
Allen, Mr. William Henry
male
35.0
0.0
0.0
373450
8.0500
NaN
S
9.736800
2.4.6:任务六:将任务二和任务三的数据合并,并保存到sex_fare_survived.csv
text. groupby( 'Sex' ) . agg( { 'Fare' : [ ( 'rename_mean' , 'mean' ) ] , 'Survived' : [ ( 'rename_sum' , 'sum' ) ] } )
Fare
Survived
rename_mean
rename_sum
Sex
female
44.479818
233
male
25.523893
109
mean= text. groupby( 'Sex' ) [ 'Fare' ] . mean( )
sur= text. groupby( 'Sex' ) [ 'Survived' ] . sum ( )
display( mean)
display( sur)
display( pd. merge( mean, sur, on= 'Sex' ) )
display( mean. to_frame( ) . join( sur) )
display( pd. concat( [ mean. to_frame( ) , sur. to_frame( ) ] , axis= 1 ) )
Sex
female 44.479818
male 25.523893
Name: Fare, dtype: float64
Sex
female 233
male 109
Name: Survived, dtype: int64
Fare
Survived
Sex
female
44.479818
233
male
25.523893
109
Fare
Survived
Sex
female
44.479818
233
male
25.523893
109
Fare
Survived
Sex
female
44.479818
233
male
25.523893
109
result = pd. merge( mean, sur, on= 'Sex' )
result. to_csv( 'sex_fare_survived.csv' )
2.4.7:任务七:得出不同年龄的总的存活人数,然后找出存活人数的最高的年龄,最后计算存活人数最高的存活率(存活人数/总人数)
text. groupby( 'Age' ) [ 'Survived' ] . sum ( )
Age
0.42 1
0.67 1
0.75 2
0.83 2
0.92 1
..
70.00 0
70.50 0
71.00 0
74.00 0
80.00 1
Name: Survived, Length: 88, dtype: int64
text. groupby( 'Age' ) [ 'Survived' ] . sum ( ) . idxmax( )
24.0
text. groupby( 'Age' ) [ 'Survived' ] . sum ( ) . loc[ 24.0 ]
15
text. groupby( 'Age' ) [ 'Survived' ] . sum ( ) . loc[ 24.0 ] / text. groupby( 'Age' ) [ 'Survived' ] . count( ) . loc[ 24.0 ]
0.5