洛谷:P1427 小鱼的数字游戏 (数组翻转)

传送门

在这里插入图片描述
思路: 没意思嘛,直接倒着输出数组即可。

代码实现:

#include<bits/stdc++.h>
#define endl '\n'
#define null NULL
#define ll long long
#define int long long
#define pii pair<int, int>
#define lowbit(x) (x &(-x))
#define ls(x) x<<1
#define rs(x) (x<<1+1)
#define me(ar) memset(ar, 0, sizeof ar)
#define mem(ar,num) memset(ar, num, sizeof ar)
#define rp(i, n) for(int i = 0, i < n; i ++)
#define rep(i, a, n) for(int i = a; i <= n; i ++)
#define pre(i, n, a) for(int i = n; i >= a; i --)
#define IOS ios::sync_with_stdio(0); cin.tie(0);cout.tie(0);
const int way[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
using namespace std;
const int  inf = 0x7fffffff;
const double PI = acos(-1.0);
const double eps = 1e-6;
const ll   mod = 1e9 + 7;
const int  N = 2e5 + 5;

int x, cnt, a[200];

signed main()
{
    IOS;

    while(cin >> x && x) a[++ cnt] = x;
    for(int i = cnt; i; i --) cout << a[i] << (i == 1 ? '\n' : ' ');

    return 0;
}

猜你喜欢

转载自blog.csdn.net/Satur9/article/details/107777458
今日推荐