直接上代码
重写 onKeyDown方法 中间的if是我自己加的判断 不需要删掉即可
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
if (MyApplication.getUserInfo() != null && MyApplication.getUserInfo().getExtend() != null && MyApplication.getUserInfo().getExtend().getUser() != null) {
exit();//退出
}else {
onBackPressed();//返回上一界面
}
return false;
}
return super.onKeyDown(keyCode, event);
}
public void exit() {
if ((System.currentTimeMillis() - exitTime) > 2000) {
Toast.makeText(getApplicationContext(), "再按一次退出程序",
Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else {
finish();
System.exit(0);
}
}