class Solution { public: bool isSymmetric2(TreeNode* lr,TreeNode* rr) { if(!lr&&!rr) return true; else if(!lr&&rr) return false; else if(lr&&!rr) return false; else if(lr->val!=rr->val) return false; else return isSymmetric2(lr->left,rr->right)&&isSymmetric2(lr->right,rr->left); } bool isSymmetric(TreeNode* root) { if(!root) return true; return isSymmetric2(root->left,root->right); } };
101. Symmetric Tree
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转载自blog.csdn.net/qq_41098649/article/details/80490293
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