Given an unsorted array, find the maximum difference between the successive elements in its sorted form.
Return 0 if the array contains less than 2 elements.
Example 1:
Input: [3,6,9,1] Output: 3 Explanation: The sorted form of the array is [1,3,6,9], either (3,6) or (6,9) has the maximum difference 3.
Example 2:
Input: [10] Output: 0 Explanation: The array contains less than 2 elements, therefore return 0.
Note:
- You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.
- Try to solve it in linear time/space.
static int x = []() { std::ios::sync_with_stdio(false); cin.tie(NULL); return 0; }(); class Solution { public: int maximumGap(vector<int>& A) { int n=A.size(); if(n<2) return 0; int mx=*max_element(A.begin(),A.end()); int mn=*min_element(A.begin(),A.end()); double len=double(mx-mn)/double(n-1); if(len==0) return 0; vector<int>mx1(n,INT_MIN),mn1(n,INT_MAX); for(int i=0;i<n;i++) { int in=(A[i]-mn)/len; mx1[in]=max(mx1[in],A[i]); mn1[in]=min(mn1[in],A[i]); } int ans=0,prev=mx1[0]; for(int i=1;i<n;i++) { if(mn1[i]==INT_MAX) continue; ans=max(ans,mn1[i]-prev); prev=mx1[i]; } return ans; } };