1396. Design Underground System

Implement the class UndergroundSystem that supports three methods:

1. checkIn(int id, string stationName, int t)

  • A customer with id card equal to id, gets in the station stationName at time t.
  • A customer can only be checked into one place at a time.

2. checkOut(int id, string stationName, int t)

  • A customer with id card equal to id, gets out from the station stationName at time t.

3. getAverageTime(string startStation, string endStation) 

  • Returns the average time to travel between the startStation and the endStation.
  • The average time is computed from all the previous traveling from startStation to endStation that happened directly.
  • Call to getAverageTime is always valid.

You can assume all calls to checkIn and checkOut methods are consistent. That is, if a customer gets in at time t1 at some station, then it gets out at time t2 with t2 > t1. All events happen in chronological order.

Example 1:

Input

["UndergroundSystem","checkIn","checkIn","checkIn","checkOut","checkOut","checkOut","getAverageTime","getAverageTime","checkIn","getAverageTime","checkOut","getAverageTime"]
[[],[45,"Leyton",3],[32,"Paradise",8],[27,"Leyton",10],[45,"Waterloo",15],[27,"Waterloo",20],[32,"Cambridge",22],["Paradise","Cambridge"],["Leyton","Waterloo"],[10,"Leyton",24],["Leyton","Waterloo"],[10,"Waterloo",38],["Leyton","Waterloo"]]

Output
[null,null,null,null,null,null,null,14.00000,11.00000,null,11.00000,null,12.00000]

Explanation
UndergroundSystem undergroundSystem = new UndergroundSystem();
undergroundSystem.checkIn(45, "Leyton", 3);
undergroundSystem.checkIn(32, "Paradise", 8);
undergroundSystem.checkIn(27, "Leyton", 10);
undergroundSystem.checkOut(45, "Waterloo", 15);
undergroundSystem.checkOut(27, "Waterloo", 20);
undergroundSystem.checkOut(32, "Cambridge", 22);
undergroundSystem.getAverageTime("Paradise", "Cambridge");       // return 14.00000. There was only one travel from "Paradise" (at time 8) to "Cambridge" (at time 22)
undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 11.00000. There were two travels from "Leyton" to "Waterloo", a customer with id=45 from time=3 to time=15 and a customer with id=27 from time=10 to time=20. So the average time is ( (15-3) + (20-10) ) / 2 = 11.00000
undergroundSystem.checkIn(10, "Leyton", 24);
undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 11.00000
undergroundSystem.checkOut(10, "Waterloo", 38);
undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 12.00000

Example 2:

Input

["UndergroundSystem","checkIn","checkOut","getAverageTime","checkIn","checkOut","getAverageTime","checkIn","checkOut","getAverageTime"]
[[],[10,"Leyton",3],[10,"Paradise",8],["Leyton","Paradise"],[5,"Leyton",10],[5,"Paradise",16],["Leyton","Paradise"],[2,"Leyton",21],[2,"Paradise",30],["Leyton","Paradise"]]

Output
[null,null,null,5.00000,null,null,5.50000,null,null,6.66667]

Explanation
UndergroundSystem undergroundSystem = new UndergroundSystem();
undergroundSystem.checkIn(10, "Leyton", 3);
undergroundSystem.checkOut(10, "Paradise", 8);
undergroundSystem.getAverageTime("Leyton", "Paradise"); // return 5.00000
undergroundSystem.checkIn(5, "Leyton", 10);
undergroundSystem.checkOut(5, "Paradise", 16);
undergroundSystem.getAverageTime("Leyton", "Paradise"); // return 5.50000
undergroundSystem.checkIn(2, "Leyton", 21);
undergroundSystem.checkOut(2, "Paradise", 30);
undergroundSystem.getAverageTime("Leyton", "Paradise"); // return 6.66667
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Constraints:

  • There will be at most 20000 operations.
  • 1 <= id, t <= 10^6
  • All strings consist of uppercase, lowercase English letters and digits.
  • 1 <= stationName.length <= 10
  • Answers within 10^-5 of the actual value will be accepted as correct.
class UndergroundSystem {
    HashMap<String, Pair<Integer, Integer>> checkoutMap = new HashMap<>(); // Route - {TotalTime, Count}
    HashMap<Integer, Pair<String, Integer>> checkInMap = new HashMap<>();  // Uid - {StationName, Time}
    
    public UndergroundSystem() {}
    
    public void checkIn(int id, String stationName, int t) {
        checkInMap.put(id, new Pair<>(stationName, t));
    }
    
    public void checkOut(int id, String stationName, int t) {
        Pair<String, Integer> checkIn = checkInMap.get(id);
        String route = checkIn.getKey() + "_" + stationName;
        int totalTime = t - checkIn.getValue();
        Pair<Integer, Integer> checkout = checkoutMap.getOrDefault(route, new Pair<>(0, 0));
        checkoutMap.put(route, new Pair<>(checkout.getKey() + totalTime, checkout.getValue() + 1));
    }
    
    public double getAverageTime(String startStation, String endStation) {
        String route = startStation + "_" + endStation;
        Pair<Integer, Integer> checkout = checkoutMap.get(route);
        return (double) checkout.getKey() / checkout.getValue();
    }
}

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转载自www.cnblogs.com/wentiliangkaihua/p/12717922.html
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