hdu1074之状压dp

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn=99999;
struct p{
	int l,r;string s;
}a[maxn];int dp[1<<15],pre[1<<15],time[1<<15];
void print(int x)
{
	if(x==0)	return;
	int k=pre[x]-1;
	print(x-(1<<k));
	cout<<a[pre[x]].s<<endl;
}
int main()
{
	int n,t;
	cin>>t;
	while(t--)
	{
		cin>>n;
		for(int i=1;i<=n;i++)	cin>>a[i].s>>a[i].l>>a[i].r;
		memset(pre,0,sizeof(pre));memset(dp,20,sizeof(dp));
		memset(time,0,sizeof(time));
		dp[0]=0;
		for(int i=1;i<(1<<n);i++)
		{
			for(int j=n-1;j>=0;j--)//刚做完第j+1件事 
			{
				int k=1<<j;
				if(i&k)
				{
					int t=time[i-k]+a[j+1].r-a[j+1].l;
					if(t<0)	t=0;//如果提前完成,不用扣分
					if(dp[i]>dp[i-k]+t)
					{
						dp[i]=dp[i-k]+t;
						time[i]=time[i-k]+a[j+1].r;
						pre[i]=j+1;
					}	
				}
			}
		}
		cout<<dp[(1<<n)-1]<<endl;
		print((1<<n)-1);
	}
} 

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转载自www.cnblogs.com/iss-ue/p/12588764.html
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