给定一个连通图 q个询问 每次加一条边 每次求出有多少个桥 poj 3694

#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
using namespace std;
const int maxn = 101000;
vector<int> mp[maxn];
int dfn[maxn],low[maxn],pre[maxn],p[maxn],cnt,ans;
int find(int u){
	return u == pre[u]?u:(pre[u] = find(pre[u]));
}
int unio(int u,int v){
	int t1 = find(u);
	int t2 = find(v);
	if(t1 == t2) return 0;
	pre[t1] = t2;
	return 1;
}
void Tarjan(int u,int fa){
	dfn[u] = low[u] = ++cnt;
	for( int i = 0; i < mp[u].size(); i++){
		int v = mp[u][i];
		if(v == fa) continue;
		if(!dfn[v]){
			p[v] = u;
			Tarjan(v,u);
			low[u] = min(low[u],low[v]);
			if(low[v] > dfn[u]){
				ans++;
			}else unio(u,v);
		}else{
			low[u] = min(low[u],dfn[v]);
		}
	}
} 
void lca(int u,int v){
	if(dfn[v] < dfn[u]) swap(v,u);
	 while(dfn[v] > dfn[u]){
	 	if(unio(v,p[v])) ans--;
	 	v = p[v];
	 }
	 while(v != u){
	 	if(unio(u,p[u])) ans--;
	 	u = p[u];
	 }
}
int main(){
	int n,m,q,u,v,t=1;
	while(scanf("%d%d",&n,&m) == 2 && m+n){
		ans = cnt = 0;
		for( int i = 0; i <= n; i++){
			pre[i] = i;
		}
		while(m--){
			scanf("%d%d",&u,&v);
			mp[u].push_back(v);
			mp[v].push_back(u);
		}
		p[1] = 1;
		Tarjan(1,1);
		scanf("%d",&q);
		printf("Case %d:\n",t++);
		while(q--){
			scanf("%d%d",&u,&v);
			lca(u,v);
			printf("%d\n",ans);
		}
		printf("\n");
	}
	return 0;
}

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转载自blog.csdn.net/sky_zdk/article/details/79629551